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internbootcamp/bootcamp/ccolorstripe/ccolorstripe.py
Executable file
213
internbootcamp/bootcamp/ccolorstripe/ccolorstripe.py
Executable file
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"""#
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### 谜题描述
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A colored stripe is represented by a horizontal row of n square cells, each cell is pained one of k colors. Your task is to repaint the minimum number of cells so that no two neighbouring cells are of the same color. You can use any color from 1 to k to repaint the cells.
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Input
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The first input line contains two integers n and k (1 ≤ n ≤ 5·105; 2 ≤ k ≤ 26). The second line contains n uppercase English letters. Letter \"A\" stands for the first color, letter \"B\" stands for the second color and so on. The first k English letters may be used. Each letter represents the color of the corresponding cell of the stripe.
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Output
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Print a single integer — the required minimum number of repaintings. In the second line print any possible variant of the repainted stripe.
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Examples
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Input
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6 3
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ABBACC
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Output
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2
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ABCACA
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Input
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3 2
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BBB
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Output
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1
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BAB
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Here is a reference code to solve this task. You can use this to help you genereate cases or validate the solution.
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```python
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args = raw_input().split()
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n = int(args[0]); k = int(args[1])
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s = list(raw_input())
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if k > 2:
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s += '_'
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cnt = 0
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for i in range(1, n):
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if s[i] == s[i - 1]:
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s[i] = (set(['A','B','C']) - set([s[i - 1], s[i + 1]])).pop(); cnt += 1
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if s[0] == s[1]:
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if s[0] == 'A':
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s[0] = 'B'
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else:
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s[0] = 'A'
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print cnt
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print ''.join(s[:-1])
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else:
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def diff(x, y):
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res = 0
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for i in range(len(x)):
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if x[i] != y[i]:
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res += 1
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return res
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res1 = ('AB' * (n / 2 + 1))[:n]; cnt1 = diff(s, res1)
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res2 = ('BA' * (n / 2 + 1))[:n]; cnt2 = diff(s, res2)
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if cnt1 < cnt2:
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cnt = cnt1; rs = ''.join(res1)
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else:
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cnt = cnt2; rs = ''.join(res2)
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print str(cnt) + '\n' + rs
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```
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请完成上述谜题的训练场环境类实现,包括所有必要的方法。
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"""
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from bootcamp import Basebootcamp
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import random
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import string
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import re
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from bootcamp import Basebootcamp
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def solve_min_repaint(n, k, s_str):
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if n == 0:
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return 0, ""
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s = list(s_str)
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if k > 2:
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modified = False
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for i in range(1, n):
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if s[i] == s[i-1]:
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available = set(string.ascii_uppercase[:k]) - {s[i-1]}
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if i < n-1:
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available.discard(s[i+1])
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s[i] = sorted(available)[0]
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modified = True
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if modified and s[0] == s[1]:
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available = set(string.ascii_uppercase[:k]) - {s[1]}
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if n >= 3:
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available.discard(s[2])
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s[0] = sorted(available)[0]
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cnt = sum(1 for a, b in zip(s, s_str) if a != b)
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return cnt, ''.join(s)
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else:
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pattern1 = ['A' if i%2 ==0 else 'B' for i in range(n)]
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pattern2 = ['B' if i%2 ==0 else 'A' for i in range(n)]
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cnt1 = sum(c != sc for c, sc in zip(pattern1, s))
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cnt2 = sum(c != sc for c, sc in zip(pattern2, s))
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if cnt1 <= cnt2:
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return cnt1, ''.join(pattern1)
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return cnt2, ''.join(pattern2)
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class Ccolorstripebootcamp(Basebootcamp):
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def __init__(self, n_min=1, n_max=10, k_min=2, k_max=4):
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self.n_min = max(n_min, 1)
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self.n_max = n_max
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self.k_min = max(k_min, 2)
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self.k_max = min(k_max, 26)
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def case_generator(self):
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n = random.randint(self.n_min, self.n_max)
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k = random.randint(self.k_min, self.k_max)
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# 生成具有非连续重复的初始字符串
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colors = string.ascii_uppercase[:k]
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if n == 1:
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original_s = random.choice(colors)
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else:
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original_s = [random.choice(colors)]
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for _ in range(1, n):
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# 保证至少有一个可能的重复
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if len(original_s) < 2 or random.random() < 0.4:
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original_s.append(original_s[-1])
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else:
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original_s.append(random.choice([c for c in colors if c != original_s[-1]]))
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original_s = ''.join(original_s)
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# 确保问题有解
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min_repaints, correct_s = solve_min_repaint(n, k, original_s)
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return {
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'n': n,
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'k': k,
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'original_s': original_s,
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'min_repaints': min_repaints,
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'correct_s': correct_s
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}
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@staticmethod
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def prompt_func(question_case) -> str:
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n = question_case['n']
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k = question_case['k']
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original_s = question_case['original_s']
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color_desc = "、".join(string.ascii_uppercase[:k])
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return f"""作为颜色优化专家,请将{n}个单元格的颜色条纹({original_s})重新涂色,要求:
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⒈ 相邻颜色不能相同
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⒉ 只能使用{color_desc}这{k}种颜色
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⒊ 修改次数最少
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请按以下格式输出答案:
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[answer]
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修改次数
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最终颜色序列
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[/answer]
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示例(k=3时):
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输入:6 3 ABBACC
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回答:
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[answer]
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2
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ABCACA
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[/answer]"""
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@staticmethod
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def extract_output(output):
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answer_blocks = re.findall(r'\[answer\](.*?)\[\/answer\]', output, re.DOTALL)
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if not answer_blocks:
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return None
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last_answer = answer_blocks[-1].strip()
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lines = [line.strip() for line in last_answer.split('\n') if line.strip()]
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return '\n'.join(lines[:2]) if len(lines)>=2 else None
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@classmethod
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def _verify_correction(cls, solution, identity):
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if not solution:
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return False
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try:
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lines = solution.split('\n')
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if len(lines) < 2:
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return False
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reported = int(lines[0].strip())
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result = lines[1].upper().strip()
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# 基础验证
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n = identity['n']
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k = identity['k']
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if len(result) != n:
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return False
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if any(c not in string.ascii_uppercase[:k] for c in result):
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return False
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# 相邻验证
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for i in range(n-1):
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if result[i] == result[i+1]:
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return False
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# 修改次数验证
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actual = sum(1 for a, b in zip(identity['original_s'], result) if a != b)
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return actual == reported == identity['min_repaints']
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except:
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return False
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