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"""#
### 谜题描述
Ashishgup and FastestFinger play a game.
They start with a number n and play in turns. In each turn, a player can make any one of the following moves:
* Divide n by any of its odd divisors greater than 1.
* Subtract 1 from n if n is greater than 1.
Divisors of a number include the number itself.
The player who is unable to make a move loses the game.
Ashishgup moves first. Determine the winner of the game if both of them play optimally.
Input
The first line contains a single integer t (1 t 100) the number of test cases. The description of the test cases follows.
The only line of each test case contains a single integer n (1 n 10^9).
Output
For each test case, print \"Ashishgup\" if he wins, and \"FastestFinger\" otherwise (without quotes).
Example
Input
7
1
2
3
4
5
6
12
Output
FastestFinger
Ashishgup
Ashishgup
FastestFinger
Ashishgup
FastestFinger
Ashishgup
Note
In the first test case, n = 1, Ashishgup cannot make a move. He loses.
In the second test case, n = 2, Ashishgup subtracts 1 on the first move. Now n = 1, FastestFinger cannot make a move, so he loses.
In the third test case, n = 3, Ashishgup divides by 3 on the first move. Now n = 1, FastestFinger cannot make a move, so he loses.
In the last test case, n = 12, Ashishgup divides it by 3. Now n = 4, FastestFinger is forced to subtract 1, and Ashishgup gets 3, so he wins by dividing it by 3.
Here is a reference code to solve this task. You can use this to help you genereate cases or validate the solution.
```python
import math
test_cases=int(input())
res=[]
for i in range(test_cases):
n=int(input())
t=0
while n%2==0:
n=n//2
t+=1
if t==0:
if n==1:
res.append(\"FastestFinger\")
else:
res.append(\"Ashishgup\")
elif t==1:
if n==1:
res.append(\"Ashishgup\")
else:
cp=0
for j in range(3,int(math.floor(math.sqrt(n)))+1,2):
#print(j)
if n%j ==0:
cp=1
break
if cp==1:
res.append(\"Ashishgup\")
else:
res.append(\"FastestFinger\")
else:
if n==1:
res.append(\"FastestFinger\")
else:
res.append(\"Ashishgup\")
'''cp=0
for j in range(3,n//2,2):
if n%j ==0:
cp=1
break
if cp==1:
res.append(\"FastestFinger\")
else:
res.append(\"Ashishgup\")'''
for i in range(test_cases):
print(res[i])
```
请完成上述谜题的训练场环境类实现包括所有必要的方法
"""
from bootcamp import Basebootcamp
import re
import math
import random
from bootcamp import Basebootcamp
class Cnumbergamebootcamp(Basebootcamp):
def __init__(self, **params):
self.min_n = max(1, params.get('min_n', 1))
self.max_n = params.get('max_n', 10**9)
self.params = params
def case_generator(self):
def generate_valid_n():
for _ in range(1000): # 增加尝试次数
case_type = random.choice([
'edge_1', 'edge_2', 'prime', 'power_of_2',
'two_times_prime', 'two_times_composite', 'complex_case'
])
if case_type == 'edge_1':
n = 1
elif case_type == 'edge_2':
n = 2
elif case_type == 'prime':
n = self._generate_odd_prime()
elif case_type == 'power_of_2':
max_exp = math.floor(math.log2(self.max_n))
if max_exp < 2:
continue # 无法生成合理2^n
exp = random.randint(2, max_exp)
n = 2 ** exp
elif case_type == 'two_times_prime':
max_p = self.max_n // 2
min_p = max(3, self.min_n // 2)
if min_p > max_p:
continue
p = self._generate_odd_prime(min_p, max_p)
n = 2 * p
elif case_type == 'two_times_composite':
max_c = self.max_n // 2
if max_c < 9: # 最小奇合数9
continue
c = self._generate_odd_composite(3, max_c)
n = 2 * c
elif case_type == 'complex_case':
max_t = math.floor(math.log2(self.max_n))
if max_t < 2:
continue
t = random.randint(2, min(5, max_t))
base = 2 ** t
remaining = self.max_n // base
if remaining < 3:
continue
factors = self._generate_odd_composite(3, remaining)
n = base * factors
if self.min_n <= n <= self.max_n:
return n
return random.randint(self.min_n, self.max_n)
n = generate_valid_n()
return {
'n': n,
'correct_answer': self.get_correct_answer(n)
}
def _generate_odd_prime(self, min_p=3, max_p=None):
max_p = max_p or self.max_n // 2
if min_p % 2 == 0:
min_p += 1
attempts = 0
while attempts < 1000:
p = random.randint(min_p, max_p)
if p % 2 == 0:
continue
if self.is_prime(p):
return p
attempts += 1
return 3 # fallback
def _generate_odd_composite(self, min_val=9, max_val=None):
max_val = max_val or self.max_n // 2
while True:
num = random.randint(min_val, max_val)
if num % 2 == 0:
continue
if not self.is_prime(num):
return num
@staticmethod
def is_prime(num):
if num < 2:
return False
if num % 2 == 0:
return num == 2
for i in range(3, int(math.isqrt(num)) + 1, 2):
if num % i == 0:
return False
return True
@staticmethod
def get_correct_answer(n):
original_n = n
t = 0
while n % 2 == 0:
n = n // 2
t += 1
k = n
if t == 0:
return "FastestFinger" if k == 1 else "Ashishgup"
elif t == 1:
if k == 1:
return "Ashishgup"
is_prime = Cnumbergamebootcamp.is_prime(k)
return "FastestFinger" if is_prime else "Ashishgup"
else:
return "FastestFinger" if k == 1 else "Ashishgup"
@staticmethod
def prompt_func(question_case):
n = question_case['n']
return f"""Ashishgup和FastestFinger在玩一个数字游戏。规则如下
- 初始数字为{n}玩家轮流进行操作Ashishgup先手
- 每个回合可以选择以下操作之一
a) 将当前数除以一个大于1的奇数因子
b) 当当前数>1减去1
无法操作的玩家失败两人都采用最优策略
请分析游戏过程并输出获胜者姓名将答案置于[answer]标签内例如
[answer]Ashishgup[/answer]"""
@staticmethod
def extract_output(output):
matches = re.findall(r'\[answer\]\s*(.*?)\s*\[/answer\]', output, re.IGNORECASE)
if not matches:
return None
last_answer = matches[-1].strip().capitalize()
return last_answer if last_answer in ['Ashishgup', 'FastestFinger'] else None
@classmethod
def _verify_correction(cls, solution, identity):
return solution == identity.get('correct_answer')