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"""#
### 谜题描述
Sereja has a sequence that consists of n positive integers, a1, a2, ..., an.
First Sereja took a piece of squared paper and wrote all distinct non-empty non-decreasing subsequences of sequence a. Then for each sequence written on the squared paper, Sereja wrote on a piece of lines paper all sequences that do not exceed it.
A sequence of positive integers x = x1, x2, ..., xr doesn't exceed a sequence of positive integers y = y1, y2, ..., yr, if the following inequation holds: x1 ≤ y1, x2 ≤ y2, ..., xr ≤ yr.
Now Sereja wonders, how many sequences are written on the lines piece of paper. Help Sereja, find the required quantity modulo 1000000007 (109 + 7).
Input
The first line contains integer n (1 n 105). The second line contains n integers a1, a2, ..., an (1 ai 106).
Output
In the single line print the answer to the problem modulo 1000000007 (109 + 7).
Examples
Input
1
42
Output
42
Input
3
1 2 2
Output
13
Input
5
1 2 3 4 5
Output
719
Here is a reference code to solve this task. You can use this to help you genereate cases or validate the solution.
```python
n = input()
a = map(int, raw_input().split())
mod = int(1e+9) + 7
size = max(a)
tree = [0] * (size + 1)
def query(index):
res = 0
while index:
res = (res + tree[index]) % mod
index -= index & -index
return res
def update(index, delta):
while index <= size:
tree[index] = (tree[index] + delta) % mod
index += index & -index
def query_one(index):
res = tree[index]
bot = index - (index & -index)
index -= 1
while index > bot:
res -= tree[index]
if res < 0: res += mod
index -= index & -index
return res
for x in a:
value = query(x) * x + x
update(x, value - query_one(x))
print query(size)
```
请完成上述谜题的训练场环境类实现包括所有必要的方法
"""
from bootcamp import Basebootcamp
import random
import re
from bootcamp import Basebootcamp
class Eserejaandsubsequencesbootcamp(Basebootcamp):
def __init__(self, min_n=1, max_n=5, min_val=1, max_val=10, seed=None):
self.min_n = min_n
self.max_n = max_n
self.min_val = min_val
self.max_val = max_val
self.seed = seed
if seed is not None:
random.seed(seed)
def case_generator(self):
n = random.randint(self.min_n, self.max_n)
a = [random.randint(self.min_val, self.max_val) for _ in range(n)]
answer = self.compute_answer(a)
return {
'n': n,
'a': a,
'answer': answer
}
@staticmethod
def compute_answer(a):
mod = 10**9 + 7
if not a:
return 0
max_val = max(a)
tree = [0] * (max_val + 2) # Extra space to avoid index issues
last = {}
total = 0
for x in a:
# Query sum of all elements <= x
sum_prev = 0
idx = x
while idx > 0:
sum_prev = (sum_prev + tree[idx]) % mod
idx -= idx & -idx
# Calculate new contribution
new_contrib = (sum_prev * x + x) % mod
delta = (new_contrib - last.get(x, 0)) % mod
# Update Fenwick tree
idx = x
while idx <= max_val:
tree[idx] = (tree[idx] + delta) % mod
idx += idx & -idx
# Update last and total
last[x] = new_contrib
total = (total + delta) % mod
return total
@staticmethod
def prompt_func(question_case):
n = question_case['n']
a = question_case['a']
a_str = ' '.join(map(str, a))
problem_text = f"""Sereja有一个由n个正整数组成的序列a。你需要解决以下问题
问题描述
找出所有不同的非空非递减子序列y然后对于每个y计算所有可能的序列x的数量其中x的长度与y相同并且每个对应的元素x_i y_i所有x的数量的总和模1000000007即为答案
子序列定义
- 子序列的元素保持原序列中的相对顺序但可以删除某些元素
- 非递减子序列中的每个元素不小于前一个元素
- 不同的子序列由它们的元素序列决定即相同的元素序列被视为同一个子序列即使它们来自原序列的不同位置
输入格式
- 第一行包含整数n1 n 1e5
- 第二行包含n个正整数a_1, a_2, ..., a_n1 a_i 1e6
你的任务
给定n和序列a计算最终的答案并以模1e9+7输出
输入样例
{n}
{a_str}
请按照上述输入样例的格式计算出正确的答案并将最终答案用[answer][/answer]标签包裹例如[answer]42[/answer]"""
return problem_text
@staticmethod
def extract_output(output):
matches = re.findall(r'\[answer\](.*?)\[/answer\]', output, re.DOTALL)
if not matches:
return None
last_match = matches[-1].strip()
digits = re.sub(r'\D', '', last_match)
try:
return int(digits) % (10**9 + 7)
except ValueError:
return None
@classmethod
def _verify_correction(cls, solution, identity):
correct_answer = identity.get('answer')
return solution == correct_answer