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"""# 谜题训练场开发任务
## 任务概述
你是一位资深程序员我需要你帮我实现一个特定谜题的训练场环境类这个类继承自`Basebootcamp`用于生成谜题实例并验证解答
## 背景说明
我正在开发一系列谜题训练场每个训练场对应一个特定类型的谜题训练场类命名为`{PuzzleName}bootcamp`其中`PuzzleName`是谜题的名称
每个训练场类主要提供两个核心功能
1. 生成该谜题类型的问题实例
2. 验证用户对问题的回答是否正确
## 技术接口规范
### 类方法实现要求
```python
class {PuzzleName}bootcamp(Basebootcamp):
def __init__(self, **params):
\"\"\"
请你自定义params以保存该puzzle相关的参数例如网格大小等参数配有默认值
\"\"\"
pass
def case_generator(self):
\"\"\"
生成谜题实例提示为保证谜题有解可以先生成结果再对结果处理得到谜题
返回一个可JSON序列化的字典避免包含set等无法通过json.dumps处理的数据结构
\"\"\"
pass
@staticmethod
def prompt_func(question_case) -> str:
\"\"\"
将case_generator生成的谜题实例转换为文本形式的问题问题中包含问题背景对谜题规则的介绍具体要解决的谜题实例期望最终答案的格式
例如你是xxxx请你解答yyyy规则如下yyyy最终答案放置在zzzzz
参数:
question_case: 由case_generator生成的谜题实例
返回:
str: 格式化的问题字符串
注意:
1. 需考虑问题的格式以便后续能正确提取
2. 问题描述中应包含期望的答案格式说明以便后续能正确提取为了避免抽取时匹配出干扰项请要求模型将答案放在特定标签[answer] [/answer]
\"\"\"
pass
@staticmethod
def extract_output(output):
\"\"\"
从LLM的回复中提取符合格式要求的答案如有多个请抽取最后一个避免使用re.search等只抽取第一个结果的方式
参数:
output: LLM的完整输出包含原始问题和回答
返回:
提取的答案若未找到符合格式的答案则返回None
\"\"\"
pass
@classmethod
def _verify_correction(cls, solution, identity):
\"\"\"
验证提取的答案是否正确注意一个问题可以能有多个解按照谜题规则进行检验不要直接匹配可能的答案
参数:
solution: extract_output提取的答案
identity: case_generator生成的谜题实例
返回:
bool: 答案是否正确
\"\"\"
pass
```
### 验证评分方法(基类已实现)
```python
@classmethod
def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
\"\"\"
验证输出结果并评分
参数:
model_output: 模型的完整输出
identity: 谜题实例由case_generator生成
format_score: 答案格式正确时的基础分数
返回:
float: 评分结果0-1之间
\"\"\"
score = 0.
try:
extract_solution = cls.extract_output(model_output)
if extract_solution is None:
return score
else:
score = format_score # 格式正确时的基础分数
if cls._verify_correction(extract_solution, identity):
score = 1. # 答案完全正确时的满分
except Exception as e:
# 处理异常情况
pass
return score
```
### 使用示例
```python
# 初始化谜题训练场
bootcamp = Puzzlebootcamp()
# 生成谜题实例
case = bootcamp.case_generator()
# 将谜题转换为文本问题
prompt = Puzzlebootcamp.prompt_func(case)
# 获取LLM对问题的解答
response = get_response(prompt, \"LLM\")
# 从完整对话中提取答案
extracted_output = Puzzlebootcamp.extract_output(prompt + response)
# 验证答案并评分
score = Puzzlebootcamp.verify_score(extracted_output, case)
```
## 你的任务
请根据以下谜题描述谜题描述可能不完整请先结合你的知识澄清规则实现一个完整的谜题训练场类
### 谜题描述
**Objective**: Divide a grid into non-overlapping regions called \"galaxies,\" each containing exactly one central circle.
**Key Rules**:
1. **Symmetry**: Every galaxy must be rotationally symmetric around its central circle (180-degree rotation). This means each cell in the galaxy has a \"mirror\" cell positioned opposite the center.
2. **Contiguity**: All cells in a galaxy must form a single connected region (adjacent horizontally or vertically).
3. **Completeness**: Every grid cell must belong to exactly one galaxy.
**How It Works**:
- The grid contains pre-placed central circles. Your goal is to outline regions where each:
- Encloses exactly one center.
- Follows symmetry: If a cell is at position (x, y) relative to the center, there must be a corresponding cell at (-x, -y).
- Is connected and fills the grid without overlaps or gaps.
请完成上述谜题的训练场环境类实现包括所有必要的方法
"""
from bootcamp import Basebootcamp
import re
from ast import literal_eval
from collections import deque
class Galaxiesbootcamp(Basebootcamp):
def __init__(self, rows=5, cols=5):
# Ensure odd dimensions for valid center placement
self.rows = rows if rows % 2 != 0 else rows + 1
self.cols = cols if cols % 2 != 0 else cols + 1
def case_generator(self):
"""Generates a puzzle case with center(s) in a grid"""
center = (self.rows // 2, self.cols // 2)
return {
'rows': self.rows,
'cols': self.cols,
'centers': [center]
}
@staticmethod
def prompt_func(question_case) -> str:
"""Generates problem description text with formatting instructions"""
centers = question_case['centers']
return f"""你是专业星系谜题解题专家,请根据以下信息划分星系:
**网格尺寸**: {question_case['rows']}x{question_case['cols']}
**中心位置**: {', '.join(f'({r},{c})' for r, c in centers)}
**规则要求**:
1. 每个星系必须包含且仅包含一个中心且形状关于中心180度对称
2. 所有单元格必须属于且仅属于一个星系
3. 星系区域必须连通上下左右相邻
请按以下格式返回答案
[answer]
[
{{"center": (行坐标, 列坐标), "cells": [(坐标1), (坐标2), ...]}},
...
]
[/answer]
请确保
1. 使用严格的Python列表和元组语法
2. 包含所有中心对应的星系
3. 每个坐标均为(row, column)格式"""
@staticmethod
def extract_output(output):
"""Extracts last valid answer block from LLM output"""
matches = re.findall(r'\[answer\](.*?)\[/answer\]', output, re.DOTALL)
if not matches:
return None
try:
return literal_eval(matches[-1].strip())
except:
return None
@classmethod
def _verify_correction(cls, solution, identity):
"""Validates solution against puzzle constraints"""
try:
# Validate solution structure
if not cls._validate_structure(solution):
return False
# Check center consistency
if not cls._check_centers(solution, identity['centers']):
return False
# Check grid coverage
if not cls._check_coverage(solution, identity['rows'], identity['cols']):
return False
# Validate each galaxy
for galaxy in solution:
if not cls._validate_galaxy(galaxy):
return False
return True
except:
return False
@staticmethod
def _validate_structure(solution):
"""Validate basic solution structure"""
if not isinstance(solution, list):
return False
for g in solution:
if not isinstance(g, dict) or 'center' not in g or 'cells' not in g:
return False
if not isinstance(g['cells'], list) or len(g['cells']) == 0:
return False
return True
@staticmethod
def _check_centers(solution, expected_centers):
"""Verify all expected centers are present"""
solution_centers = {tuple(g['center']) for g in solution}
expected_set = {tuple(c) for c in expected_centers}
return solution_centers == expected_set
@staticmethod
def _check_coverage(solution, rows, cols):
"""Verify complete grid coverage without overlaps"""
all_cells = []
for g in solution:
all_cells.extend(map(tuple, g['cells']))
expected = {(r, c) for r in range(rows) for c in range(cols)}
return len(all_cells) == len(expected) and set(all_cells) == expected
@classmethod
def _validate_galaxy(cls, galaxy):
"""Validate individual galaxy constraints"""
cells = [tuple(c) for c in galaxy['cells']]
center = tuple(galaxy['center'])
# Check center presence
if center not in cells:
return False
# Check symmetry
cx, cy = center
for (x, y) in cells:
sym = (2*cx - x, 2*cy - y)
if sym not in cells:
return False
# Check connectivity
return cls._is_connected(cells)
@staticmethod
def _is_connected(cells):
"""BFS check for region connectivity"""
if not cells:
return False
visited = set()
q = deque([cells[0]])
visited.add(cells[0])
while q:
x, y = q.popleft()
for dx, dy in [(-1,0),(1,0),(0,-1),(0,1)]:
neighbor = (x+dx, y+dy)
if neighbor in cells and neighbor not in visited:
visited.add(neighbor)
q.append(neighbor)
return len(visited) == len(cells)