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"""# 谜题训练场开发任务
## 任务概述
你是一位资深程序员我需要你帮我实现一个特定谜题的训练场环境类这个类继承自`Basebootcamp`用于生成谜题实例并验证解答
## 背景说明
我正在开发一系列谜题训练场每个训练场对应一个特定类型的谜题训练场类命名为`{PuzzleName}bootcamp`其中`PuzzleName`是谜题的名称
每个训练场类主要提供两个核心功能
1. 生成该谜题类型的问题实例
2. 验证用户对问题的回答是否正确
## 技术接口规范
### 类方法实现要求
```python
class {PuzzleName}bootcamp(Basebootcamp):
def __init__(self, **params):
\"\"\"
请你自定义params以保存该puzzle相关的参数例如网格大小等参数配有默认值
\"\"\"
pass
def case_generator(self):
\"\"\"
生成谜题实例提示为保证谜题有解可以先生成结果再对结果处理得到谜题
返回一个可JSON序列化的字典避免包含set等无法通过json.dumps处理的数据结构
\"\"\"
pass
@staticmethod
def prompt_func(question_case) -> str:
\"\"\"
将case_generator生成的谜题实例转换为文本形式的问题问题中包含问题背景对谜题规则的介绍具体要解决的谜题实例期望最终答案的格式
例如你是xxxx请你解答yyyy规则如下yyyy最终答案放置在zzzzz
参数:
question_case: 由case_generator生成的谜题实例
返回:
str: 格式化的问题字符串
注意:
1. 需考虑问题的格式以便后续能正确提取
2. 问题描述中应包含期望的答案格式说明以便后续能正确提取为了避免抽取时匹配出干扰项请要求模型将答案放在特定标签[answer] [/answer]
\"\"\"
pass
@staticmethod
def extract_output(output):
\"\"\"
从LLM的回复中提取符合格式要求的答案如有多个请抽取最后一个避免使用re.search等只抽取第一个结果的方式
参数:
output: LLM的完整输出包含原始问题和回答
返回:
提取的答案若未找到符合格式的答案则返回None
\"\"\"
pass
@classmethod
def _verify_correction(cls, solution, identity):
\"\"\"
验证提取的答案是否正确注意一个问题可以能有多个解按照谜题规则进行检验不要直接匹配可能的答案
参数:
solution: extract_output提取的答案
identity: case_generator生成的谜题实例
返回:
bool: 答案是否正确
\"\"\"
pass
```
### 验证评分方法(基类已实现)
```python
@classmethod
def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
\"\"\"
验证输出结果并评分
参数:
model_output: 模型的完整输出
identity: 谜题实例由case_generator生成
format_score: 答案格式正确时的基础分数
返回:
float: 评分结果0-1之间
\"\"\"
score = 0.
try:
extract_solution = cls.extract_output(model_output)
if extract_solution is None:
return score
else:
score = format_score # 格式正确时的基础分数
if cls._verify_correction(extract_solution, identity):
score = 1. # 答案完全正确时的满分
except Exception as e:
# 处理异常情况
pass
return score
```
### 使用示例
```python
# 初始化谜题训练场
bootcamp = Puzzlebootcamp()
# 生成谜题实例
case = bootcamp.case_generator()
# 将谜题转换为文本问题
prompt = Puzzlebootcamp.prompt_func(case)
# 获取LLM对问题的解答
response = get_response(prompt, \"LLM\")
# 从完整对话中提取答案
extracted_output = Puzzlebootcamp.extract_output(prompt + response)
# 验证答案并评分
score = Puzzlebootcamp.verify_score(extracted_output, case)
```
## 你的任务
请根据以下谜题描述谜题描述可能不完整请先结合你的知识澄清规则实现一个完整的谜题训练场类
### 谜题描述
**Heyawake Puzzle Rules Explained:**
1. **Grid Structure**:
- Played on a rectangular grid divided into polyomino regions (\"rooms\").
- Some rooms contain a number; others are unnumbered.
2. **Black Cell Placement**:
- **Isolation**: No two black cells may be adjacent horizontally or vertically (diagonal is allowed).
- **Room Constraints**:
- A room with a number **N** must contain exactly **N** black cells.
- Unnumbered rooms can have any number of black cells (including zero).
3. **White Cell Connectivity**:
- All white (uncolored) cells must form **a single contiguous area** connected edge-to-edge (diagonals do not count).
4. **Stripe Prevention (Three Rooms Rule)**:
- In any row or column, a straight line of white cells cannot span **three or more rooms** without interruption by at least one black cell. This prevents white \"stripes\" crossing multiple rooms.
请完成上述谜题的训练场环境类实现包括所有必要的方法
"""
from bootcamp import Basebootcamp
import re
from collections import deque
class Heyawakebootcamp(Basebootcamp):
def __init__(self, rows=3, cols=3):
self.rows = rows
self.cols = cols
def case_generator(self):
# 生成一个简单的谜题实例房间0的number为0确保有解
rows = self.rows
cols = self.cols
rooms = [
{
'cells': [(0, 0)],
'number': 0
},
{
'cells': [(i, j) for i in range(rows) for j in range(cols) if (i, j) != (0, 0)]
# 无number
}
]
return {
'rows': rows,
'cols': cols,
'rooms': rooms
}
@staticmethod
def prompt_func(question_case) -> str:
rows = question_case['rows']
cols = question_case['cols']
rooms = question_case['rooms']
problem_desc = "请解决以下Heyawake谜题\n\n"
problem_desc += "谜题规则:\n"
problem_desc += "1. 黑格不能水平或垂直相邻。\n"
problem_desc += "2. 每个带有数字的房间必须包含恰好该数字的黑格。未带数字的房间可以有任何数量的黑格。\n"
problem_desc += "3. 所有白格必须形成一个连通的区域。\n"
problem_desc += "4. 同一行或列中的连续白格不能跨越三个或更多不同的房间。\n\n"
problem_desc += f"网格尺寸:{rows}行×{cols}列。\n"
problem_desc += "房间划分及其数字说明:\n"
for idx, room in enumerate(rooms):
cells = room['cells']
number = room.get('number', None)
cells_str = ', '.join(f'({r},{c})' for r, c in cells)
problem_desc += f"- 房间{idx+1}包含单元格 {cells_str}"
if number is not None:
problem_desc += f",必须恰好有 {number} 个黑格"
problem_desc += "\n"
problem_desc += "\n将答案以二维数组0为白格1为黑格放在[answer]标签内,例如:\n[answer]\n[[0, 0, 0],\n[0, 1, 0],\n[0, 0, 0]]\n[/answer]"
return problem_desc
@staticmethod
def extract_output(output):
pattern = r'\[answer\](.*?)\[/answer\]'
matches = re.findall(pattern, output, re.DOTALL)
if not matches:
return None
last_match = matches[-1].strip()
try:
solution = eval(last_match)
if isinstance(solution, list) and all(isinstance(row, list) for row in solution):
return solution
return None
except:
return None
@classmethod
def _verify_correction(cls, solution, identity):
# 验证solution结构合法性
rows = identity['rows']
cols = identity['cols']
rooms = identity['rooms']
if (not isinstance(solution, list) or len(solution) != rows or
any(not isinstance(row, list) or len(row) != cols for row in solution)):
return False
for row in solution:
for cell in row:
if cell not in (0, 1):
return False
# 规则1黑格不能相邻
for i in range(rows):
for j in range(cols):
if solution[i][j] == 1:
if j+1 < cols and solution[i][j+1] == 1:
return False
if i+1 < rows and solution[i+1][j] == 1:
return False
# 规则2房间约束
for room in rooms:
cells = room['cells']
if 'number' in room:
required = room['number']
actual = sum(solution[i][j] for (i, j) in cells)
if actual != required:
return False
# 规则3白格连通性
white = [(i, j) for i in range(rows) for j in range(cols) if solution[i][j] == 0]
if not white:
return False
visited = set()
queue = deque([white[0]])
visited.add(white[0])
directions = [(-1,0), (1,0), (0,-1), (0,1)]
while queue:
i, j = queue.popleft()
for dx, dy in directions:
ni, nj = i+dx, j+dy
if 0 <= ni < rows and 0 <= nj < cols and solution[ni][nj] == 0:
if (ni, nj) not in visited:
visited.add((ni, nj))
queue.append((ni, nj))
if len(visited) != len(white):
return False
# 规则4条纹防止规则
# 构建房间映射
room_id = [[-1 for _ in range(cols)] for _ in range(rows)]
for idx, room in enumerate(rooms):
for i, j in room['cells']:
room_id[i][j] = idx
# 检查行
for i in range(rows):
current_rooms = []
for j in range(cols):
if solution[i][j] == 1:
if len(current_rooms) >= 3:
return False
current_rooms = []
else:
rid = room_id[i][j]
if not current_rooms or rid != current_rooms[-1]:
current_rooms.append(rid)
if len(current_rooms) >= 3:
return False
if len(current_rooms) >= 3:
return False
# 检查列
for j in range(cols):
current_rooms = []
for i in range(rows):
if solution[i][j] == 1:
if len(current_rooms) >= 3:
return False
current_rooms = []
else:
rid = room_id[i][j]
if not current_rooms or rid != current_rooms[-1]:
current_rooms.append(rid)
if len(current_rooms) >= 3:
return False
if len(current_rooms) >= 3:
return False
return True