mirror of
https://github.com/InternLM/InternBootcamp.git
synced 2026-04-30 17:40:42 +00:00
init-commit
This commit is contained in:
commit
18a552597a
3461 changed files with 1150579 additions and 0 deletions
391
internbootcamp/bootcamp/kor_logic_resolution/kor_logic_resolution.py
Executable file
391
internbootcamp/bootcamp/kor_logic_resolution/kor_logic_resolution.py
Executable file
|
|
@ -0,0 +1,391 @@
|
|||
"""# 谜题训练场开发任务
|
||||
|
||||
## 任务概述
|
||||
你是一位资深程序员,我需要你帮我实现一个特定谜题的训练场环境类。这个类继承自`Basebootcamp`,用于生成谜题实例并验证解答。
|
||||
|
||||
## 背景说明
|
||||
我正在开发一系列谜题训练场,每个训练场对应一个特定类型的谜题。训练场类命名为`{PuzzleName}bootcamp`,其中`PuzzleName`是谜题的名称。
|
||||
|
||||
每个训练场类主要提供两个核心功能:
|
||||
1. 生成该谜题类型的问题实例
|
||||
2. 验证用户对问题的回答是否正确
|
||||
|
||||
## 技术接口规范
|
||||
|
||||
### 类方法实现要求
|
||||
|
||||
```python
|
||||
from bootcamp import Basebootcamp
|
||||
|
||||
class {PuzzleName}bootcamp(Basebootcamp):
|
||||
def __init__(self, **params):
|
||||
\"\"\"
|
||||
请你自定义params,以保存该puzzle相关的参数,例如网格大小等,参数配有默认值
|
||||
\"\"\"
|
||||
pass
|
||||
|
||||
def case_generator(self):
|
||||
\"\"\"
|
||||
生成谜题实例,提示:为保证谜题有解,可以先生成结果再对结果处理得到谜题
|
||||
返回:一个可JSON序列化的字典(避免包含set等无法通过json.dumps处理的数据结构)
|
||||
\"\"\"
|
||||
pass
|
||||
|
||||
@staticmethod
|
||||
def prompt_func(question_case) -> str:
|
||||
\"\"\"
|
||||
将case_generator生成的谜题实例转换为文本形式的问题,问题中包含问题背景、对谜题规则的介绍、具体要解决的谜题实例、期望最终答案的格式,
|
||||
例如:你是xxxx,请你解答yyyy,规则如下:yyyy,最终答案放置在:zzzzz
|
||||
注意:请参照提供的谜题描述进行复述,规则应当描述详细,包括任务背景、具体任务操作规则、对题目格式和答案格式的含义介绍等,
|
||||
|
||||
参数:
|
||||
question_case: 由case_generator生成的谜题实例
|
||||
|
||||
返回:
|
||||
str: 格式化的问题字符串
|
||||
|
||||
注意:
|
||||
1. 需考虑问题的格式,以便后续能正确提取
|
||||
2. 问题描述中应包含期望的答案格式说明,以便后续能正确提取,为了避免抽取时匹配出干扰项,请要求模型将答案放在特定标签(如双括号)内,例如[[your answer here]]
|
||||
\"\"\"
|
||||
pass
|
||||
|
||||
@staticmethod
|
||||
def extract_output(output):
|
||||
\"\"\"
|
||||
从LLM的回复中提取符合格式要求的答案,如有多个,请抽取最后一个,避免使用re.search等只抽取第一个结果的方式。
|
||||
|
||||
参数:
|
||||
output: LLM的完整输出(包含原始问题和回答)
|
||||
|
||||
返回:
|
||||
提取的答案,若未找到符合格式的答案则返回None
|
||||
\"\"\"
|
||||
pass
|
||||
|
||||
@classmethod
|
||||
def _verify_correction(cls, solution, identity):
|
||||
\"\"\"
|
||||
验证提取的答案是否正确,注意一个问题可以能有多个解,按照谜题规则进行检验,不要直接匹配可能的答案。
|
||||
|
||||
参数:
|
||||
solution: extract_output提取的答案
|
||||
identity: case_generator生成的谜题实例
|
||||
|
||||
返回:
|
||||
bool: 答案是否正确
|
||||
\"\"\"
|
||||
pass
|
||||
```
|
||||
|
||||
### 验证评分方法(基类已实现)
|
||||
|
||||
```python
|
||||
@classmethod
|
||||
def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
|
||||
\"\"\"
|
||||
验证输出结果并评分。
|
||||
|
||||
参数:
|
||||
model_output: 模型的完整输出
|
||||
identity: 谜题实例(由case_generator生成)
|
||||
format_score: 答案格式正确时的基础分数
|
||||
|
||||
返回:
|
||||
float: 评分结果(0-1之间)
|
||||
\"\"\"
|
||||
score = 0.
|
||||
try:
|
||||
extract_solution = cls.extract_output(model_output)
|
||||
if extract_solution is None:
|
||||
return score
|
||||
else:
|
||||
score = format_score # 格式正确时的基础分数
|
||||
if cls._verify_correction(extract_solution, identity):
|
||||
score = 1. # 答案完全正确时的满分
|
||||
except Exception as e:
|
||||
# 处理异常情况
|
||||
pass
|
||||
return score
|
||||
```
|
||||
|
||||
### 使用示例
|
||||
|
||||
```python
|
||||
# 初始化谜题训练场
|
||||
bootcamp = Puzzlebootcamp()
|
||||
|
||||
# 生成谜题实例
|
||||
case = bootcamp.case_generator()
|
||||
|
||||
# 将谜题转换为文本问题
|
||||
prompt = Puzzlebootcamp.prompt_func(case)
|
||||
|
||||
# 获取LLM对问题的解答
|
||||
response = get_response(prompt, \"LLM\")
|
||||
|
||||
# 从完整对话中提取答案
|
||||
extracted_output = Puzzlebootcamp.extract_output(prompt + response)
|
||||
|
||||
# 验证答案并评分
|
||||
score = Puzzlebootcamp.verify_score(extracted_output, case)
|
||||
```
|
||||
|
||||
## 你的任务
|
||||
请根据以下谜题描述(谜题描述可能不完整,请先结合你的知识澄清规则),实现一个完整的谜题训练场类:
|
||||
|
||||
### 谜题描述
|
||||
Literal: A propositional variable and its negation are collectively referred to as literals.
|
||||
|
||||
Complement: If L is a literal, then the complement of L is denoted as L’. If L = p, then L’ = ¬p; if L = ¬p, then L’ = p.
|
||||
|
||||
Resolution: Suppose simple disjunctive clause C1 = C3 ∨ L, C2 = C4 ∨ L’, then C1 and C2 can be resolved, and it is defined that dispel(C1, C2) = C3 ∨ C4. If it is empty, then dispel(C1, C2) = 0.
|
||||
|
||||
Resolution Algorithm: The steps to determine if a conjunctive normal form has a satisfying assignment are as follows:
|
||||
1. Input: Conjunctive normal form S.
|
||||
2. Output: If S has a satisfying assignment, output “Plausible”; otherwise, output “Implausible”.
|
||||
3. Steps:
|
||||
1. Initialization:
|
||||
- Let S0 and S2 be empty sets.
|
||||
- Let S1 be the set of all simple disjunctive clauses in S.
|
||||
2. Resolve clauses in S0 and S1:
|
||||
- For each simple disjunctive clause C1 in S0 and each simple disjunctive clause C2 in S1:
|
||||
- If C1 and C2 can be resolved, calculate C = dispel(C1, C2).
|
||||
- If C = 0, output “Implausible” and terminate the calculation.
|
||||
- If neither S0 nor S1 contains C, add C to S2.
|
||||
3. Resolve clauses in S1:
|
||||
- For each pair of clauses C1 and C2 in S1:
|
||||
- If C1 and C2 can be resolved, calculate C = dispel(C1, C2).
|
||||
- If C = 0, output “Implausible” and terminate the calculation.
|
||||
- If neither S0 nor S1 contains C, add C to S2.
|
||||
4. Check S2:
|
||||
- If S2 contains no elements, output “Plausible” and terminate the calculation.
|
||||
- Otherwise, add S1 to S0, set S1 to S2, clear S2, and return to step b.Example questions are as follows:
|
||||
|
||||
<example 0>
|
||||
Can clauses C1 = p ∨ q and C2 = p ∨ r be resolved?
|
||||
A. Yes
|
||||
B.No
|
||||
Answer format: [[option]].
|
||||
</example 0>
|
||||
|
||||
<example 1>
|
||||
If C1 = ¬p ∨ ¬q ∨ r and C2 = ¬q ∨ ¬r ∨ s ∨ ¬t,
|
||||
what is dispel(C1, C2)?
|
||||
Please provide your answer in the format [[]].
|
||||
</example 1>
|
||||
|
||||
<example 2>
|
||||
If C1 = p ∨ ¬q ∨ r ∨ ¬s, C2 = s,
|
||||
then dispel(C1, C2) = ?
|
||||
Please provide the answer in the format [[]].
|
||||
</example 2>
|
||||
|
||||
<example 3>
|
||||
If C1 = ¬p ∨ q ∨ r and C2 = p ∨ ¬r ∨ ¬s,
|
||||
then dispel(C1, C2) = ?
|
||||
Provide the answer in the format [[]],
|
||||
or [[];[];…] if there are multiple answers.
|
||||
</example 3>
|
||||
|
||||
<example 4>
|
||||
Regarding (¬p ∨ q)∧(p ∨ q) ∧ (q),
|
||||
what are S0, S1, and S2 before starting the resolution algorithm,
|
||||
and why is S2 after the first loop iteration?
|
||||
Provide the answers in the format [[];[];[];[]],
|
||||
where sets are represented using {},
|
||||
and an empty set is denoted by ∅.
|
||||
</example 4>
|
||||
|
||||
<example 5>
|
||||
For (¬p ∨ q)∧(p ∨ q) ∧ (q),
|
||||
what is the output of the resolution algorithm?
|
||||
How many cycles will it iterate?
|
||||
Please provide the answer in the format [[output];[number]].
|
||||
</example 5>
|
||||
|
||||
<example 6>
|
||||
For p∧(p∨q)∧(p∨¬q)∧(q∨¬r)∧(q∨r),
|
||||
what are S0, S1, and S2 before the second cycle of the resolution algorithm?
|
||||
Provide the answers in the format [[];[];[]],
|
||||
where sets are represented using {},
|
||||
and an empty set is denoted by ∅.
|
||||
</example 6>
|
||||
|
||||
<example 7>
|
||||
For p∧(p∨q)∧(p∨¬q)∧(q∨¬r)∧(q∨r),
|
||||
what is the output of the resolution algorithm?
|
||||
How many cycles will it iterate?
|
||||
Please provide the answer in the format [[output];[number]].
|
||||
</example 7>
|
||||
|
||||
<example 8>
|
||||
For (p∨q)∧(p∨¬q)∧(¬p∨r),
|
||||
what is S2 at the end of the first cycle of the resolution algorithm?
|
||||
Provide the answer in the format [[]],
|
||||
using {} for sets and ∅ for an empty set.
|
||||
</example 8>
|
||||
|
||||
<example 9>
|
||||
For (p∨q)∧(p∨¬q)∧(¬p∨r),
|
||||
what is the output of the resolution algorithm?
|
||||
How many cycles will it iterate?
|
||||
Please provide the answer in the format [[output];[number]].
|
||||
</example 9>
|
||||
|
||||
|
||||
请完成上述谜题的训练场环境类实现,包括所有必要的方法。
|
||||
"""
|
||||
|
||||
from bootcamp import Basebootcamp
|
||||
import re
|
||||
import random
|
||||
from itertools import combinations
|
||||
from bootcamp import Basebootcamp
|
||||
|
||||
class KorLogicResolutionbootcamp(Basebootcamp):
|
||||
def __init__(self, **params):
|
||||
self.vars = params.get('vars', ['p', 'q', 'r', 's'])
|
||||
self.max_clause_length = params.get('max_clause_length', 3)
|
||||
self.problem_types = params.get('problem_types', ['can_resolve', 'compute_dispel', 'algorithm_output'])
|
||||
random.seed(params.get('seed', None))
|
||||
|
||||
def case_generator(self):
|
||||
problem_type = random.choice(self.problem_types)
|
||||
if problem_type == 'can_resolve':
|
||||
return self._generate_can_resolve_case()
|
||||
elif problem_type == 'compute_dispel':
|
||||
return self._generate_compute_dispel_case()
|
||||
elif problem_type == 'algorithm_output':
|
||||
return self._generate_algorithm_output_case()
|
||||
else:
|
||||
raise ValueError(f"Unknown problem type: {problem_type}")
|
||||
|
||||
@staticmethod
|
||||
def prompt_func(question_case):
|
||||
problem_type = question_case['problem_type']
|
||||
if problem_type == 'can_resolve':
|
||||
C1_str = ' ∨ '.join(question_case['C1'])
|
||||
C2_str = ' ∨ '.join(question_case['C2'])
|
||||
return f"Can clauses C1 = {C1_str} and C2 = {C2_str} be resolved?\nA. Yes\nB. No\nAnswer format: [[option]]."
|
||||
elif problem_type == 'compute_dispel':
|
||||
C1_str = ' ∨ '.join(question_case['C1'])
|
||||
C2_str = ' ∨ '.join(question_case['C2'])
|
||||
return f"If C1 = {C1_str} and C2 = {C2_str}, what is dispel(C1, C2)?\nProvide answer in format [[result]].\nFor multiple results use [[result1;result2]].\nFor empty clause write [[0]]."
|
||||
elif problem_type == 'algorithm_output':
|
||||
cnf_str = ' ∧ '.join([f'({" ∨ ".join(clause)})' for clause in question_case['cnf']])
|
||||
return f"Apply resolution algorithm to: {cnf_str}\nWhat is the output (Plausible/Implausible) and cycle count?\nAnswer format: [[output];[number]]."
|
||||
else:
|
||||
raise ValueError(f"Unknown problem type: {problem_type}")
|
||||
|
||||
@staticmethod
|
||||
def extract_output(output):
|
||||
matches = re.findall(r'\[\[(.*?)\]\]', output)
|
||||
return matches[-1].strip() if matches else None
|
||||
|
||||
@classmethod
|
||||
def _verify_correction(cls, solution, identity):
|
||||
problem_type = identity['problem_type']
|
||||
if problem_type == 'can_resolve':
|
||||
expected = identity['expected']
|
||||
ans = solution.upper()
|
||||
return (ans == 'A' and expected) or (ans == 'B' and not expected)
|
||||
|
||||
elif problem_type == 'compute_dispel':
|
||||
expected = set(identity['expected'].split(' ∨ ')) if identity['expected'] != '0' else set()
|
||||
answers = [a.strip() for a in solution.split(';')]
|
||||
for ans in answers:
|
||||
ans_set = set(ans.split(' ∨ ')) if ans != '0' else set()
|
||||
if ans_set == expected:
|
||||
return True
|
||||
return False
|
||||
|
||||
elif problem_type == 'algorithm_output':
|
||||
try:
|
||||
output_part, steps_part = solution.split(';')
|
||||
expected_output = identity['expected_output'].lower()
|
||||
return (output_part.strip().lower() == expected_output and
|
||||
int(steps_part) == identity['steps'])
|
||||
except:
|
||||
return False
|
||||
return False
|
||||
|
||||
# Helper methods
|
||||
def _generate_can_resolve_case(self):
|
||||
if random.random() < 0.5:
|
||||
var = random.choice(self.vars)
|
||||
C1 = [var] + self._gen_literals(exclude=[var])
|
||||
C2 = [f'¬{var}'] + self._gen_literals(exclude=[var])
|
||||
expected = True
|
||||
else:
|
||||
C1, C2 = self._gen_non_resolvable_clauses()
|
||||
expected = False
|
||||
return {'problem_type': 'can_resolve', 'C1': C1, 'C2': C2, 'expected': expected}
|
||||
|
||||
def _generate_compute_dispel_case(self):
|
||||
var = random.choice(self.vars)
|
||||
C1 = [var] + self._gen_literals(exclude=[var])
|
||||
C2 = [f'¬{var}'] + self._gen_literals(exclude=[var])
|
||||
resolvent = list(set([l for l in C1 if l != var] + [l for l in C2 if l != f'¬{var}']))
|
||||
expected = ' ∨ '.join(resolvent) if resolvent else '0'
|
||||
return {'problem_type': 'compute_dispel', 'C1': C1, 'C2': C2, 'expected': expected}
|
||||
|
||||
def _generate_algorithm_output_case(self):
|
||||
cnf = [['p'], ['¬p']] if random.random() < 0.5 else [self._gen_clause()]
|
||||
output, steps = self._run_resolution(cnf)
|
||||
return {'problem_type': 'algorithm_output', 'cnf': cnf,
|
||||
'expected_output': output, 'steps': steps}
|
||||
|
||||
def _gen_literals(self, exclude=[]):
|
||||
return list(set([self._gen_literal(exclude) for _ in range(random.randint(0, self.max_clause_length-1))]))
|
||||
|
||||
def _gen_literal(self, exclude):
|
||||
available = [v for v in self.vars if v not in exclude and f'¬{v}' not in exclude]
|
||||
var = random.choice(available) if available else random.choice(self.vars)
|
||||
return f'¬{var}' if random.random() < 0.5 else var
|
||||
|
||||
def _gen_non_resolvable_clauses(self):
|
||||
while True:
|
||||
C1 = self._gen_clause()
|
||||
C2 = self._gen_clause()
|
||||
if not self._can_resolve(C1, C2):
|
||||
return C1, C2
|
||||
|
||||
def _gen_clause(self):
|
||||
return list(set([self._gen_literal([]) for _ in range(random.randint(1, self.max_clause_length))]))
|
||||
|
||||
def _can_resolve(self, C1, C2):
|
||||
return any(('¬'+l in C2 or l[1:] in C2) for l in C1)
|
||||
|
||||
def _run_resolution(self, cnf):
|
||||
S0, S1, steps = set(), {frozenset(c) for c in cnf}, 0
|
||||
while True:
|
||||
S2 = set()
|
||||
# Resolve S0 and S1
|
||||
for C0 in S0:
|
||||
for C1 in S1:
|
||||
if resolvents := self._resolve(C0, C1):
|
||||
if any(not r for r in resolvents):
|
||||
return 'Implausible', steps + 1
|
||||
S2.update(r for r in resolvents if r not in S0 and r not in S1)
|
||||
# Resolve S1 with itself
|
||||
for C1, C2 in combinations(S1, 2):
|
||||
if resolvents := self._resolve(C1, C2):
|
||||
if any(not r for r in resolvents):
|
||||
return 'Implausible', steps + 1
|
||||
S2.update(r for r in resolvents if r not in S0 and r not in S1)
|
||||
if not S2:
|
||||
return 'Plausible', steps + 1
|
||||
S0.update(S1)
|
||||
S1 = S2
|
||||
steps += 1
|
||||
|
||||
def _resolve(self, C1, C2):
|
||||
resolved = []
|
||||
C1_set, C2_set = set(C1), set(C2)
|
||||
for l in C1_set:
|
||||
comp = f'¬{l}' if not l.startswith('¬') else l[1:]
|
||||
if comp in C2_set:
|
||||
new_clause = (C1_set - {l}) | (C2_set - {comp})
|
||||
resolved.append(frozenset(new_clause))
|
||||
return resolved
|
||||
Loading…
Add table
Add a link
Reference in a new issue