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"""# 谜题训练场开发任务
## 任务概述
你是一位资深程序员我需要你帮我实现一个特定谜题的训练场环境类这个类继承自`Basebootcamp`用于生成谜题实例并验证解答
## 背景说明
我正在开发一系列谜题训练场每个训练场对应一个特定类型的谜题训练场类命名为`{PuzzleName}bootcamp`其中`PuzzleName`是谜题的名称
每个训练场类主要提供两个核心功能
1. 生成该谜题类型的问题实例
2. 验证用户对问题的回答是否正确
## 技术接口规范
### 类方法实现要求
```python
from bootcamp import Basebootcamp
class {PuzzleName}bootcamp(Basebootcamp):
def __init__(self, **params):
\"\"\"
请你自定义params以保存该puzzle相关的参数例如网格大小等参数配有默认值
\"\"\"
pass
def case_generator(self):
\"\"\"
生成谜题实例提示为保证谜题有解可以先生成结果再对结果处理得到谜题
返回一个可JSON序列化的字典避免包含set等无法通过json.dumps处理的数据结构
\"\"\"
pass
@staticmethod
def prompt_func(question_case) -> str:
\"\"\"
将case_generator生成的谜题实例转换为文本形式的问题问题中包含问题背景对谜题规则的介绍具体要解决的谜题实例期望最终答案的格式
例如你是xxxx请你解答yyyy规则如下yyyy最终答案放置在zzzzz
注意请参照提供的谜题描述进行复述规则应当描述详细包括任务背景具体任务操作规则对题目格式和答案格式的含义介绍等
参数:
question_case: 由case_generator生成的谜题实例
返回:
str: 格式化的问题字符串
注意:
1. 需考虑问题的格式以便后续能正确提取
2. 问题描述中应包含期望的答案格式说明以便后续能正确提取为了避免抽取时匹配出干扰项请要求模型将答案放在特定标签如双括号例如[[your answer here]]
\"\"\"
pass
@staticmethod
def extract_output(output):
\"\"\"
从LLM的回复中提取符合格式要求的答案如有多个请抽取最后一个避免使用re.search等只抽取第一个结果的方式
参数:
output: LLM的完整输出包含原始问题和回答
返回:
提取的答案若未找到符合格式的答案则返回None
\"\"\"
pass
@classmethod
def _verify_correction(cls, solution, identity):
\"\"\"
验证提取的答案是否正确注意一个问题可以能有多个解按照谜题规则进行检验不要直接匹配可能的答案
参数:
solution: extract_output提取的答案
identity: case_generator生成的谜题实例
返回:
bool: 答案是否正确
\"\"\"
pass
```
### 验证评分方法(基类已实现)
```python
@classmethod
def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
\"\"\"
验证输出结果并评分
参数:
model_output: 模型的完整输出
identity: 谜题实例由case_generator生成
format_score: 答案格式正确时的基础分数
返回:
float: 评分结果0-1之间
\"\"\"
score = 0.
try:
extract_solution = cls.extract_output(model_output)
if extract_solution is None:
return score
else:
score = format_score # 格式正确时的基础分数
if cls._verify_correction(extract_solution, identity):
score = 1. # 答案完全正确时的满分
except Exception as e:
# 处理异常情况
pass
return score
```
### 使用示例
```python
# 初始化谜题训练场
bootcamp = Puzzlebootcamp()
# 生成谜题实例
case = bootcamp.case_generator()
# 将谜题转换为文本问题
prompt = Puzzlebootcamp.prompt_func(case)
# 获取LLM对问题的解答
response = get_response(prompt, \"LLM\")
# 从完整对话中提取答案
extracted_output = Puzzlebootcamp.extract_output(prompt + response)
# 验证答案并评分
score = Puzzlebootcamp.verify_score(extracted_output, case)
```
## 你的任务
请根据以下谜题描述谜题描述可能不完整请先结合你的知识澄清规则实现一个完整的谜题训练场类
### 谜题描述
Literal: A propositional variable and its negation are collectively referred to as literals.
Complement: If L is a literal, then the complement of L is denoted as L. If L = p, then L = ¬p; if L = ¬p, then L = p.
Resolution: Suppose simple disjunctive clause C1 = C3 L, C2 = C4 L, then C1 and C2 can be resolved, and it is defined that dispel(C1, C2) = C3 C4. If it is empty, then dispel(C1, C2) = 0.
Resolution Algorithm: The steps to determine if a conjunctive normal form has a satisfying assignment are as follows:
1. Input: Conjunctive normal form S.
2. Output: If S has a satisfying assignment, output Plausible; otherwise, output Implausible.
3. Steps:
1. Initialization:
- Let S0 and S2 be empty sets.
- Let S1 be the set of all simple disjunctive clauses in S.
2. Resolve clauses in S0 and S1:
- For each simple disjunctive clause C1 in S0 and each simple disjunctive clause C2 in S1:
- If C1 and C2 can be resolved, calculate C = dispel(C1, C2).
- If C = 0, output Implausible and terminate the calculation.
- If neither S0 nor S1 contains C, add C to S2.
3. Resolve clauses in S1:
- For each pair of clauses C1 and C2 in S1:
- If C1 and C2 can be resolved, calculate C = dispel(C1, C2).
- If C = 0, output Implausible and terminate the calculation.
- If neither S0 nor S1 contains C, add C to S2.
4. Check S2:
- If S2 contains no elements, output Plausible and terminate the calculation.
- Otherwise, add S1 to S0, set S1 to S2, clear S2, and return to step b.Example questions are as follows:
<example 0>
Can clauses C1 = p q and C2 = p r be resolved?
A. Yes
B.No
Answer format: [[option]].
</example 0>
<example 1>
If C1 = ¬p ¬q r and C2 = ¬q ¬r s ¬t,
what is dispel(C1, C2)?
Please provide your answer in the format [[]].
</example 1>
<example 2>
If C1 = p ¬q r ¬s, C2 = s,
then dispel(C1, C2) = ?
Please provide the answer in the format [[]].
</example 2>
<example 3>
If C1 = ¬p q r and C2 = p ¬r ¬s,
then dispel(C1, C2) = ?
Provide the answer in the format [[]],
or [[];[];] if there are multiple answers.
</example 3>
<example 4>
Regarding (¬p q)(p q) (q),
what are S0, S1, and S2 before starting the resolution algorithm,
and why is S2 after the first loop iteration?
Provide the answers in the format [[];[];[];[]],
where sets are represented using {},
and an empty set is denoted by .
</example 4>
<example 5>
For (¬p q)(p q) (q),
what is the output of the resolution algorithm?
How many cycles will it iterate?
Please provide the answer in the format [[output];[number]].
</example 5>
<example 6>
For p(pq)(p¬q)(q¬r)(qr),
what are S0, S1, and S2 before the second cycle of the resolution algorithm?
Provide the answers in the format [[];[];[]],
where sets are represented using {},
and an empty set is denoted by .
</example 6>
<example 7>
For p(pq)(p¬q)(q¬r)(qr),
what is the output of the resolution algorithm?
How many cycles will it iterate?
Please provide the answer in the format [[output];[number]].
</example 7>
<example 8>
For (pq)(p¬q)(¬pr),
what is S2 at the end of the first cycle of the resolution algorithm?
Provide the answer in the format [[]],
using {} for sets and for an empty set.
</example 8>
<example 9>
For (pq)(p¬q)(¬pr),
what is the output of the resolution algorithm?
How many cycles will it iterate?
Please provide the answer in the format [[output];[number]].
</example 9>
请完成上述谜题的训练场环境类实现包括所有必要的方法
"""
from bootcamp import Basebootcamp
import re
import random
from itertools import combinations
from bootcamp import Basebootcamp
class KorLogicResolutionbootcamp(Basebootcamp):
def __init__(self, **params):
self.vars = params.get('vars', ['p', 'q', 'r', 's'])
self.max_clause_length = params.get('max_clause_length', 3)
self.problem_types = params.get('problem_types', ['can_resolve', 'compute_dispel', 'algorithm_output'])
random.seed(params.get('seed', None))
def case_generator(self):
problem_type = random.choice(self.problem_types)
if problem_type == 'can_resolve':
return self._generate_can_resolve_case()
elif problem_type == 'compute_dispel':
return self._generate_compute_dispel_case()
elif problem_type == 'algorithm_output':
return self._generate_algorithm_output_case()
else:
raise ValueError(f"Unknown problem type: {problem_type}")
@staticmethod
def prompt_func(question_case):
problem_type = question_case['problem_type']
if problem_type == 'can_resolve':
C1_str = ' '.join(question_case['C1'])
C2_str = ' '.join(question_case['C2'])
return f"Can clauses C1 = {C1_str} and C2 = {C2_str} be resolved?\nA. Yes\nB. No\nAnswer format: [[option]]."
elif problem_type == 'compute_dispel':
C1_str = ' '.join(question_case['C1'])
C2_str = ' '.join(question_case['C2'])
return f"If C1 = {C1_str} and C2 = {C2_str}, what is dispel(C1, C2)?\nProvide answer in format [[result]].\nFor multiple results use [[result1;result2]].\nFor empty clause write [[0]]."
elif problem_type == 'algorithm_output':
cnf_str = ''.join([f'({" ".join(clause)})' for clause in question_case['cnf']])
return f"Apply resolution algorithm to: {cnf_str}\nWhat is the output (Plausible/Implausible) and cycle count?\nAnswer format: [[output];[number]]."
else:
raise ValueError(f"Unknown problem type: {problem_type}")
@staticmethod
def extract_output(output):
matches = re.findall(r'\[\[(.*?)\]\]', output)
return matches[-1].strip() if matches else None
@classmethod
def _verify_correction(cls, solution, identity):
problem_type = identity['problem_type']
if problem_type == 'can_resolve':
expected = identity['expected']
ans = solution.upper()
return (ans == 'A' and expected) or (ans == 'B' and not expected)
elif problem_type == 'compute_dispel':
expected = set(identity['expected'].split(' ')) if identity['expected'] != '0' else set()
answers = [a.strip() for a in solution.split(';')]
for ans in answers:
ans_set = set(ans.split(' ')) if ans != '0' else set()
if ans_set == expected:
return True
return False
elif problem_type == 'algorithm_output':
try:
output_part, steps_part = solution.split(';')
expected_output = identity['expected_output'].lower()
return (output_part.strip().lower() == expected_output and
int(steps_part) == identity['steps'])
except:
return False
return False
# Helper methods
def _generate_can_resolve_case(self):
if random.random() < 0.5:
var = random.choice(self.vars)
C1 = [var] + self._gen_literals(exclude=[var])
C2 = [f'¬{var}'] + self._gen_literals(exclude=[var])
expected = True
else:
C1, C2 = self._gen_non_resolvable_clauses()
expected = False
return {'problem_type': 'can_resolve', 'C1': C1, 'C2': C2, 'expected': expected}
def _generate_compute_dispel_case(self):
var = random.choice(self.vars)
C1 = [var] + self._gen_literals(exclude=[var])
C2 = [f'¬{var}'] + self._gen_literals(exclude=[var])
resolvent = list(set([l for l in C1 if l != var] + [l for l in C2 if l != f'¬{var}']))
expected = ' '.join(resolvent) if resolvent else '0'
return {'problem_type': 'compute_dispel', 'C1': C1, 'C2': C2, 'expected': expected}
def _generate_algorithm_output_case(self):
cnf = [['p'], ['¬p']] if random.random() < 0.5 else [self._gen_clause()]
output, steps = self._run_resolution(cnf)
return {'problem_type': 'algorithm_output', 'cnf': cnf,
'expected_output': output, 'steps': steps}
def _gen_literals(self, exclude=[]):
return list(set([self._gen_literal(exclude) for _ in range(random.randint(0, self.max_clause_length-1))]))
def _gen_literal(self, exclude):
available = [v for v in self.vars if v not in exclude and f'¬{v}' not in exclude]
var = random.choice(available) if available else random.choice(self.vars)
return f'¬{var}' if random.random() < 0.5 else var
def _gen_non_resolvable_clauses(self):
while True:
C1 = self._gen_clause()
C2 = self._gen_clause()
if not self._can_resolve(C1, C2):
return C1, C2
def _gen_clause(self):
return list(set([self._gen_literal([]) for _ in range(random.randint(1, self.max_clause_length))]))
def _can_resolve(self, C1, C2):
return any(('¬'+l in C2 or l[1:] in C2) for l in C1)
def _run_resolution(self, cnf):
S0, S1, steps = set(), {frozenset(c) for c in cnf}, 0
while True:
S2 = set()
# Resolve S0 and S1
for C0 in S0:
for C1 in S1:
if resolvents := self._resolve(C0, C1):
if any(not r for r in resolvents):
return 'Implausible', steps + 1
S2.update(r for r in resolvents if r not in S0 and r not in S1)
# Resolve S1 with itself
for C1, C2 in combinations(S1, 2):
if resolvents := self._resolve(C1, C2):
if any(not r for r in resolvents):
return 'Implausible', steps + 1
S2.update(r for r in resolvents if r not in S0 and r not in S1)
if not S2:
return 'Plausible', steps + 1
S0.update(S1)
S1 = S2
steps += 1
def _resolve(self, C1, C2):
resolved = []
C1_set, C2_set = set(C1), set(C2)
for l in C1_set:
comp = f'¬{l}' if not l.startswith('¬') else l[1:]
if comp in C2_set:
new_clause = (C1_set - {l}) | (C2_set - {comp})
resolved.append(frozenset(new_clause))
return resolved