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internbootcamp/bootcamp/kor_operation_unicode0033/kor_operation_unicode0033.py
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internbootcamp/bootcamp/kor_operation_unicode0033/kor_operation_unicode0033.py
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"""# 谜题训练场开发任务
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## 任务概述
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你是一位资深程序员,我需要你帮我实现一个特定谜题的训练场环境类。这个类继承自`Basebootcamp`,用于生成谜题实例并验证解答。
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## 背景说明
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我正在开发一系列谜题训练场,每个训练场对应一个特定类型的谜题。训练场类命名为`{PuzzleName}bootcamp`,其中`PuzzleName`是谜题的名称。
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每个训练场类主要提供两个核心功能:
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1. 生成该谜题类型的问题实例
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2. 验证用户对问题的回答是否正确
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## 技术接口规范
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### 类方法实现要求
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```python
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from bootcamp import Basebootcamp
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class {PuzzleName}bootcamp(Basebootcamp):
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def __init__(self, **params):
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\"\"\"
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请你自定义params,以保存该puzzle相关的参数,例如网格大小等,参数配有默认值
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\"\"\"
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pass
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def case_generator(self):
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\"\"\"
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生成谜题实例,提示:为保证谜题有解,可以先生成结果再对结果处理得到谜题
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返回:一个可JSON序列化的字典(避免包含set等无法通过json.dumps处理的数据结构)
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\"\"\"
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pass
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@staticmethod
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def prompt_func(question_case) -> str:
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\"\"\"
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将case_generator生成的谜题实例转换为文本形式的问题,问题中包含问题背景、对谜题规则的介绍、具体要解决的谜题实例、期望最终答案的格式,
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例如:你是xxxx,请你解答yyyy,规则如下:yyyy,最终答案放置在:zzzzz
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注意:请参照提供的谜题描述进行复述,规则应当描述详细,包括任务背景、具体任务操作规则、对题目格式和答案格式的含义介绍等,
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参数:
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question_case: 由case_generator生成的谜题实例
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返回:
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str: 格式化的问题字符串
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注意:
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1. 需考虑问题的格式,以便后续能正确提取
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2. 问题描述中应包含期望的答案格式说明,以便后续能正确提取,为了避免抽取时匹配出干扰项,请要求模型将答案放在特定标签(如双括号)内,例如[[your answer here]]
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\"\"\"
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pass
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@staticmethod
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def extract_output(output):
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\"\"\"
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从LLM的回复中提取符合格式要求的答案,如有多个,请抽取最后一个,避免使用re.search等只抽取第一个结果的方式。
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参数:
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output: LLM的完整输出(包含原始问题和回答)
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返回:
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提取的答案,若未找到符合格式的答案则返回None
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\"\"\"
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pass
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@classmethod
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def _verify_correction(cls, solution, identity):
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\"\"\"
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验证提取的答案是否正确,注意一个问题可以能有多个解,按照谜题规则进行检验,不要直接匹配可能的答案。
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参数:
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solution: extract_output提取的答案
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identity: case_generator生成的谜题实例
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返回:
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bool: 答案是否正确
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\"\"\"
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pass
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```
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### 验证评分方法(基类已实现)
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```python
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@classmethod
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def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
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\"\"\"
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验证输出结果并评分。
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参数:
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model_output: 模型的完整输出
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identity: 谜题实例(由case_generator生成)
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format_score: 答案格式正确时的基础分数
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返回:
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float: 评分结果(0-1之间)
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\"\"\"
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score = 0.
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try:
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extract_solution = cls.extract_output(model_output)
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if extract_solution is None:
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return score
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else:
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score = format_score # 格式正确时的基础分数
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if cls._verify_correction(extract_solution, identity):
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score = 1. # 答案完全正确时的满分
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except Exception as e:
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# 处理异常情况
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pass
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return score
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```
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### 使用示例
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```python
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# 初始化谜题训练场
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bootcamp = Puzzlebootcamp()
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# 生成谜题实例
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case = bootcamp.case_generator()
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# 将谜题转换为文本问题
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prompt = Puzzlebootcamp.prompt_func(case)
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# 获取LLM对问题的解答
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response = get_response(prompt, \"LLM\")
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# 从完整对话中提取答案
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extracted_output = Puzzlebootcamp.extract_output(prompt + response)
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# 验证答案并评分
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score = Puzzlebootcamp.verify_score(extracted_output, case)
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```
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## 你的任务
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请根据以下谜题描述(谜题描述可能不完整,请先结合你的知识澄清规则),实现一个完整的谜题训练场类:
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### 谜题描述
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a①b=\sqrt{a}+b^2.
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a②b=\sqrt{a}×b.Example questions are as follows:
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<example 0>
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Compute 9②(4①2).
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Please ensure the answer is a single number and wrap it in double square brackets, like this: [[your answer]].
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</example 0>
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<example 1>
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Compute 49①(9②2).
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Please ensure the answer is a single number and wrap it in double square brackets, like this: [[your answer]].
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</example 1>
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<example 2>
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Compute (4①3)②2.
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Please provide your answer in LaTeX format.
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If the answer is a fraction, write it as \frac{a}{b}.
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If it contains a root sign, use \sqrt{x} where x is the number under the root.
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Wrap the final answer in double square brackets, like this: [[your answer]].
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</example 2>
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<example 3>
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Compute (16①2)②3.
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Please provide your answer in LaTeX format.
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If the answer is a fraction, write it as \frac{a}{b}.
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If it contains a root sign, use \sqrt{x} where x is the number under the root.
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Wrap the final answer in double square brackets, like this: [[your answer]].
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</example 3>
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<example 4>
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If (X①3)②2=10, find X.
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The answer should only be given as a number.
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Please wrap the answer in double square brackets, like this: [[your answer]].
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</example 4>
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<example 5>
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If 4②(X①2)=20, find X.
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The answer should only be given as a number.
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Please wrap the answer in double square brackets, like this: [[your answer]].
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</example 5>
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<example 6>
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If 6①(X②4)=40, find X.
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Please provide your answer in LaTeX format.
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If the answer is a fraction, write it as \frac{a}{b}.
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If it contains a root sign, use \sqrt{x} where x is the number under the root.
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Wrap the final answer in double square brackets, like this: [[your answer]].
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</example 6>
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<example 7>
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If (X①2)②5=35, find X.
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The answer should only be given as a number.
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Please wrap the answer in double square brackets, like this: [[your answer]].
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</example 7>
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<example 8>
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If (X①2)②3=9, find X.
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The answer should only be given as a number.
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Please wrap the answer in double square brackets, like this: [[your answer]].
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</example 8>
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<example 9>
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If 4②(X①1)=12, find X.
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The answer should only be given as a number.
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Please wrap the answer in double square brackets, like this: [[your answer]].
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</example 9>
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请完成上述谜题的训练场环境类实现,包括所有必要的方法。
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"""
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from bootcamp import Basebootcamp
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import math
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import re
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import random
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from typing import Optional
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class KorOperationUnicode0033bootcamp(Basebootcamp):
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def __init__(self, compute_prob=0.5, max_square=10, operand_range=(1,5), max_depth=2):
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self.compute_prob = compute_prob
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self.max_square = max_square
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self.operand_range = operand_range
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self.max_depth = max_depth # 控制嵌套层级
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def case_generator(self):
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if random.random() < self.compute_prob:
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# 生成带随机嵌套结构的计算题
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def build_expression(depth=0):
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# 基础情况:返回数字或创建新表达式
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if depth >= self.max_depth:
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return random.randint(1, self.max_square) ** 2
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# 随机决定是否创建嵌套结构
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if random.random() < 0.5:
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# 创建新的运算符节点
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op = random.choice(['①', '②'])
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left = build_expression(depth + 1)
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right = build_expression(depth + 1)
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return {'operator': op, 'left': left, 'right': right}
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else:
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# 返回基本数字
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return random.randint(1, self.max_square) ** 2
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return {
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'type': 'compute',
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'expression': build_expression()
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}
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else:
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# 生成解方程题(保持原逻辑)
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a = random.randint(1, self.operand_range[1])
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m = random.randint(a+1, a+5)
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X = (m**2 - a**2) ** 2
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b = random.randint(1, self.operand_range[1])
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c = m * b
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return {
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'type': 'solve',
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'equation': {'a': a, 'b': b, 'c': c},
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'X': X
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}
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@staticmethod
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def prompt_func(question_case) -> str:
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definition = """a①b=\sqrt{a}+b^2.
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a②b=\sqrt{a}×b.
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"""
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if question_case['type'] == 'compute':
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expr_str = KorOperationUnicode0033bootcamp.expression_to_str(question_case['expression'])
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latex_rules = ("Please provide your answer in LaTeX format. "
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"Use \\frac{a}{b} for fractions and \\sqrt{x} for roots. "
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"Put your final answer within [[ ]].")
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return definition + f"Compute {expr_str}.\n{latex_rules}"
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else:
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eq = question_case['equation']
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return definition + (f"If (X①{eq['a']})②{eq['b']} = {eq['c']}, find X.\n"
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"Provide only a numeric answer within [[ ]].")
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@staticmethod
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def expression_to_str(expr) -> str:
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if isinstance(expr, dict):
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left = KorOperationUnicode0033bootcamp.expression_to_str(expr['left'])
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right = KorOperationUnicode0033bootcamp.expression_to_str(expr['right'])
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return f"({left}{expr['operator']}{right})"
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return str(expr)
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@staticmethod
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def extract_output(output: str) -> Optional[str]:
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matches = re.findall(r'\[\[(.*?)\]\]', output)
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return matches[-1].strip() if matches else None
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@classmethod
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def _verify_correction(cls, solution: str, identity: dict) -> bool:
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try:
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if identity['type'] == 'compute':
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actual = cls.parse_solution(solution)
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expected = cls.compute_expression(identity['expression'])
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return math.isclose(actual, expected, rel_tol=1e-9)
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else:
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X = int(solution)
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a = identity['equation']['a']
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b = identity['equation']['b']
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c = identity['equation']['c']
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return math.isclose(math.sqrt(math.sqrt(X) + a**2) * b, c, rel_tol=1e-9)
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except:
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return False
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@staticmethod
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def compute_expression(expr) -> float:
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if isinstance(expr, dict):
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left = KorOperationUnicode0033bootcamp.compute_expression(expr['left'])
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right = KorOperationUnicode0033bootcamp.compute_expression(expr['right'])
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if expr['operator'] == '①':
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return math.sqrt(left) + right**2
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return math.sqrt(left) * right
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return float(expr)
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@staticmethod
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def parse_solution(solution: str) -> float:
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solution = solution.replace(' ', '')
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# 处理分数
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frac_match = re.match(r'\\frac\{(-?\d+)\}\{(\d+)\}', solution)
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if frac_match:
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return float(frac_match[1]) / float(frac_match[2])
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# 处理根号表达式(支持系数)
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sqrt_match = re.match(r'(-?)(\d*)\\sqrt\{(\d+)\}', solution)
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if sqrt_match:
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sign = -1 if sqrt_match[1] else 1
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coeff = float(sqrt_match[2] or 1) * sign
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return coeff * math.sqrt(float(sqrt_match[3]))
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# 处理纯根号
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if solution.startswith('\\sqrt'):
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return math.sqrt(float(re.search(r'\d+', solution).group()))
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return float(solution)
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