init-commit

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lilinyang 2025-05-23 15:27:15 +08:00
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from .BaseCipherEnvironment import BaseCipherEnvironment
import numpy as np
def generate_initial_grid(keyword):
cleaned_keyword = keyword.upper().replace('J', 'I')
cleaned_keyword = ''.join(sorted(set(cleaned_keyword), key=cleaned_keyword.index))
alphabet = 'ABCDEFGHIKLMNOPQRSTUVWXYZ'
grid = np.array(list(cleaned_keyword + ''.join(filter(lambda c: c not in cleaned_keyword, alphabet))))
grid = grid.reshape(5, 5)
return grid
def generate_subsequent_grids(initial_grid):
grids = [initial_grid]
for i in range(1, 5):
grid = np.roll(initial_grid, i, axis=0)
grids.append(grid)
for i in range(1, 4):
grid = np.roll(grids[4], i, axis=0)
grids.append(grid)
return grids
def find_position(grid, letter):
indices = np.where(grid == letter)
return indices[0][0], indices[1][0]
class KorPhillipsFigureCipherEnvironment(BaseCipherEnvironment):
def __init__(self, *args, **kwargs):
problem_description = """
Kor Phillips Figure Cipher
"""
super().__init__(problem_description, *args, **kwargs)
@property
def cipher_name(self) -> str:
return "Kor_rule7_PhillipsFigureCipher"
def encode(self, text, **kwargs):
keyword = "PHILLIPS"
# 处理输入文本,只保留字母并转为大写
message = ''.join(char.upper() for char in text if char.isalpha())
print(f"处理后的输入文本: {message}")
initial_grid = generate_initial_grid(keyword)
grids = generate_subsequent_grids(initial_grid)
encrypted_message = []
for i in range(0, len(message), 5):
block = message[i:i+5]
grid_index = (i // 5) % 8
grid = grids[grid_index]
print(f"\n处理第{i//5}个块: {block}")
print(f"使用第{grid_index}号网格")
encrypted_block = []
for letter in block:
if letter == 'J':
encrypted_block.append(letter)
print(f"字母{letter}是J直接保留")
else:
row, col = find_position(grid, letter)
encrypted_letter = grid[(row + 1) % 5, (col + 1) % 5]
print(f"字母{letter}在位置({row},{col}),向右下移动一格得到{encrypted_letter}")
encrypted_block.append(encrypted_letter)
encrypted_message.append(''.join(encrypted_block))
print(f"加密后的块: {''.join(encrypted_block)}")
result = ''.join(encrypted_message)
print(f"\n最终加密结果: {result}")
return result
def decode(self, text, **kwargs):
keyword = "PHILLIPS"
initial_grid = generate_initial_grid(keyword)
grids = generate_subsequent_grids(initial_grid)
decrypted_message = []
print(f"需要解密的文本: {text}")
for i in range(0, len(text), 5):
block = text[i:i+5]
grid_index = (i // 5) % 8
grid = grids[grid_index]
print(f"\n处理第{i//5}个块: {block}")
print(f"使用第{grid_index}号网格")
decrypted_block = []
for letter in block:
if letter == 'J':
decrypted_block.append(letter)
print(f"字母{letter}是J直接保留")
else:
row, col = find_position(grid, letter)
decrypted_letter = grid[(row - 1) % 5, (col - 1) % 5]
print(f"字母{letter}在位置({row},{col}),向左上移动一格得到{decrypted_letter}")
decrypted_block.append(decrypted_letter)
decrypted_message.append(''.join(decrypted_block))
print(f"解密后的块: {''.join(decrypted_block)}")
result = ''.join(decrypted_message)
print(f"\n最终解密结果: {result}")
return result
def get_encode_rule(self, ):
return """加密规则:
- 输入:
- 明文: 不含标点和空格的大写字母字符串
- 输出:
- 密文: 大写字母字符串
- 准备:
- 字母表 = 'ABCDEFGHIKLMNOPQRSTUVWXYZ'(不包含字母J)
- 8个网格(Grid0-Grid7)
- 加密步骤:
- 明文按5个字符分组从0开始编号
- 对于5个字符的块:
- 使用的网格由grid_index = (i // 5) % 8确定其中i是块号整数除法运算符//将左边的数除以右边的数向下取整结果
- 对于当前块中的每个字符:
- 如果字符是"J"不加密直接添加到加密块
- 否则在当前网格中找到字符的位置然后向右下方移动一个网格位置(row+1,col+1)(如果越界则在对应边界的另一侧继续)移动后位置的字母作为加密字母
- 将加密字母添加到加密块
- 处理完所有块后连接加密块形成最终加密消息"""
def get_decode_rule(self, ):
return """解密规则:
- 输入:
- 密文: 大写字母字符串
- 输出:
- 明文: 大写字母字符串
- 准备:
- 字母表 = 'ABCDEFGHIKLMNOPQRSTUVWXYZ'(不包含字母J)
- 8个网格(与加密相同)
- 解密步骤:
- 将密文分成5个字符的块:
- 例如如果密文是"KHOORTQHQTHHSAUQ"第0块是"KHOOR"第1块是"TQHQH"以此类推(从0开始编号)
- 确定用于当前块的网格:
计算grid_index = (i // 5) % 8从网格列表中选择适当的网格i是块号
- 对于块中的每个字符:
- 如果字符是"J": 直接将"J"添加到解密块不进行解密
- 否则在网格中找到字符的位置通过向左上方移动一格获得(如果越界则在对应边界的另一侧继续)移动后位置的字母作为解密字母
- 将解密字母添加到解密块
- 处理完块中所有字符后将解密块添加到解密消息列表形成最终解密消息"""