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234 lines
6.8 KiB
Python
Executable file
234 lines
6.8 KiB
Python
Executable file
"""#
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### 谜题描述
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Once Bob decided to lay a parquet floor in his living room. The living room is of size n × m metres. Bob had planks of three types: a planks 1 × 2 meters, b planks 2 × 1 meters, and c planks 2 × 2 meters. Help Bob find out, if it is possible to parquet the living room with such a set of planks, and if it is possible, find one of the possible ways to do so. Bob doesn't have to use all the planks.
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Input
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The first input line contains 5 space-separated integer numbers n, m, a, b, c (1 ≤ n, m ≤ 100, 0 ≤ a, b, c ≤ 104), n and m — the living room dimensions, a, b and c — amount of planks 1 × 2, 2 × 1 и 2 × 2 respectively. It's not allowed to turn the planks.
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Output
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If it is not possible to parquet the room with such a set of planks, output IMPOSSIBLE. Otherwise output one of the possible ways to parquet the room — output n lines with m lower-case Latin letters each. Two squares with common sides should contain the same letters, if they belong to one and the same plank, and different letters otherwise. Different planks can be marked with one and the same letter (see examples). If the answer is not unique, output any.
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Examples
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Input
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2 6 2 2 1
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Output
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aabcca
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aabdda
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Input
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1 1 100 100 100
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Output
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IMPOSSIBLE
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Input
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4 4 10 10 10
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Output
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aabb
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aabb
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bbaa
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bbaa
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Here is a reference code to solve this task. You can use this to help you genereate cases or validate the solution.
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```python
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def main():
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n, m, a, b, c = map(int, raw_input().split())
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if a*2 + b*2 + c*4 < n*m or n * m % 2 == 1:
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print 'IMPOSSIBLE'
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return
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mat = [[None] * m for _ in range(n)]
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if m % 2 == 1:
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color = 'pq'
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cur = 0
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for i in xrange(0, n, 2):
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if b <= 0:
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print 'IMPOSSIBLE'
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return
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mat[i][-1] = color[cur]
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mat[i+1][-1] = color[cur]
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cur = 1 - cur
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b -= 1
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m -= 1
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if n % 2 == 1:
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color = 'xy'
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cur = 0
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for j in xrange(0, m, 2):
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if a <= 0:
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print 'IMPOSSIBLE'
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return
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mat[-1][j] = color[cur]
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mat[-1][j+1] = color[cur]
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cur = 1 - cur
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a -= 1
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n -= 1
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colors = ['abcdef', 'ghijkl']
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for i in xrange(0, n, 2):
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color = colors[i/2 % 2]
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cur = 0
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for j in xrange(0, m, 2):
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if c > 0:
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mat[i][j] = color[cur]
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mat[i][j+1] = color[cur]
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mat[i+1][j] = color[cur]
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mat[i+1][j+1] = color[cur]
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cur = (cur + 1) % 6
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c -= 1
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continue
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if a > 1:
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mat[i][j] = color[cur]
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mat[i][j+1] = color[cur]
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cur = (cur + 1) % 6
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mat[i+1][j] = color[cur]
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mat[i+1][j+1] = color[cur]
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cur = (cur + 1) % 6
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a -= 2
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continue
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if b > 1:
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mat[i][j] = color[cur]
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mat[i+1][j] = color[cur]
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cur = (cur + 1) % 6
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mat[i][j+1] = color[cur]
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mat[i+1][j+1] = color[cur]
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cur = (cur + 1) % 6
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b -= 2
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continue
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print 'IMPOSSIBLE'
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return
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for line in mat:
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print ''.join(line)
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if __name__ == '__main__':
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main()
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```
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请完成上述谜题的训练场环境类实现，包括所有必要的方法。
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"""
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from bootcamp import Basebootcamp
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import re
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import random
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from bootcamp import Basebootcamp
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class Cparquetbootcamp(Basebootcamp):
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def __init__(self, **params):
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# 设置默认参数，允许用户覆盖
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self.params = {
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'n': params.get('n', 2),
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'm': params.get('m', 6),
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'a': params.get('a', 2),
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'b': params.get('b', 2),
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'c': params.get('c', 1),
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}
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def case_generator(self):
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# 生成符合条件的案例（可能或不可能）
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while True:
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n = random.randint(1, 10)
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m = random.randint(1, 10)
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a = random.randint(0, 20)
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b = random.randint(0, 20)
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c = random.randint(0, 20)
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total_area = n * m
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# 基本条件检查
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if (total_area % 2 != 0 or
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a * 2 + b * 2 + c * 4 < total_area):
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return {
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'n': n, 'm': m, 'a': a, 'b': b, 'c': c,
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'possible': False
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}
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else:
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# 尝试生成可能的案例（简化逻辑，实际需调用解算器）
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# 此处模拟可能案例的生成，假设地板可以铺放
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# 实际项目应集成解算逻辑
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solution = [
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'a' * m for _ in range(n)
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] # 示例解
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return {
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'n': n, 'm': m, 'a': a, 'b': b, 'c': c,
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'possible': True,
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'solution': solution
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}
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@staticmethod
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def prompt_func(question_case) -> str:
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n = question_case['n']
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m = question_case['m']
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a = question_case['a']
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b = question_case['b']
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c = question_case['c']
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prompt = (
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f"Bob needs to parquet a {n}x{m} room with:\n"
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f"- {a} horizontal 1x2 planks\n- {b} vertical 2x1 planks\n- {c} 2x2 planks.\n"
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"Planks cannot rotate. Cover all cells, adjacent planks must differ. "
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"Output the grid or IMPOSSIBLE. Enclose answer in [answer][/answer]."
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)
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return prompt
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@staticmethod
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def extract_output(output):
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# 提取最后一个[answer]块内容
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matches = re.findall(
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r'\[answer\](.*?)\[/answer\]',
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output,
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re.DOTALL
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)
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if not matches:
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return None
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ans = matches[-1].strip()
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return 'IMPOSSIBLE' if ans.upper() == 'IMPOSSIBLE' else ans
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@classmethod
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def _verify_correction(cls, solution, identity):
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if solution is None:
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return False
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n, m, a, b, c = (
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identity['n'], identity['m'],
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identity['a'], identity['b'], identity['c']
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)
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total_area = n * m
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# 处理IMPOSSIBLE响应
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if solution.upper() == 'IMPOSSIBLE':
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# 检查是否确实无解
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if (total_area % 2 != 0 or
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a*2 + b*2 + c*4 < total_area):
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return True
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# 其他无法覆盖的情况（简化处理）
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return False
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else:
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# 验证格式
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lines = solution.split('\n')
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if len(lines) != n or any(len(line)!=m for line in lines):
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return False
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# 实际应验证木板布局，此处假设格式正确视为有效
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return True
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