InternBootcamp/internbootcamp/bootcamp/binairo/binairo.py
2025-05-23 15:27:15 +08:00

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"""# 谜题训练场开发任务
## 任务概述
你是一位资深程序员,我需要你帮我实现一个特定谜题的训练场环境类。这个类继承自`Basebootcamp`,用于生成谜题实例并验证解答。
## 背景说明
我正在开发一系列谜题训练场,每个训练场对应一个特定类型的谜题。训练场类命名为`{PuzzleName}bootcamp`,其中`PuzzleName`是谜题的名称。
每个训练场类主要提供两个核心功能:
1. 生成该谜题类型的问题实例
2. 验证用户对问题的回答是否正确
## 技术接口规范
### 类方法实现要求
```python
class {PuzzleName}bootcamp(Basebootcamp):
def __init__(self, **params):
\"\"\"
请你自定义params以保存该puzzle相关的参数例如网格大小等参数配有默认值
\"\"\"
pass
def case_generator(self):
\"\"\"
生成谜题实例,提示:为保证谜题有解,可以先生成结果再对结果处理得到谜题
返回一个可JSON序列化的字典避免包含set等无法通过json.dumps处理的数据结构
\"\"\"
pass
@staticmethod
def prompt_func(question_case) -> str:
\"\"\"
将case_generator生成的谜题实例转换为文本形式的问题问题中包含问题背景、对谜题规则的介绍、具体要解决的谜题实例、期望最终答案的格式
例如你是xxxx请你解答yyyy规则如下yyyy最终答案放置在zzzzz
参数:
question_case: 由case_generator生成的谜题实例
返回:
str: 格式化的问题字符串
注意:
1. 需考虑问题的格式,以便后续能正确提取
2. 问题描述中应包含期望的答案格式说明,以便后续能正确提取,为了避免抽取时匹配出干扰项,请要求模型将答案放在特定标签,如[answer] [/answer]内
\"\"\"
pass
@staticmethod
def extract_output(output):
\"\"\"
从LLM的回复中提取符合格式要求的答案如有多个请抽取最后一个避免使用re.search等只抽取第一个结果的方式。
参数:
output: LLM的完整输出包含原始问题和回答
返回:
提取的答案若未找到符合格式的答案则返回None
\"\"\"
pass
@classmethod
def _verify_correction(cls, solution, identity):
\"\"\"
验证提取的答案是否正确,注意一个问题可以能有多个解,按照谜题规则进行检验,不要直接匹配可能的答案。
参数:
solution: extract_output提取的答案
identity: case_generator生成的谜题实例
返回:
bool: 答案是否正确
\"\"\"
pass
```
### 验证评分方法(基类已实现)
```python
@classmethod
def verify_score(cls, model_output, identity:dict, format_score=0.1) -> float:
\"\"\"
验证输出结果并评分。
参数:
model_output: 模型的完整输出
identity: 谜题实例由case_generator生成
format_score: 答案格式正确时的基础分数
返回:
float: 评分结果0-1之间
\"\"\"
score = 0.
try:
extract_solution = cls.extract_output(model_output)
if extract_solution is None:
return score
else:
score = format_score # 格式正确时的基础分数
if cls._verify_correction(extract_solution, identity):
score = 1. # 答案完全正确时的满分
except Exception as e:
# 处理异常情况
pass
return score
```
### 使用示例
```python
# 初始化谜题训练场
bootcamp = Puzzlebootcamp()
# 生成谜题实例
case = bootcamp.case_generator()
# 将谜题转换为文本问题
prompt = Puzzlebootcamp.prompt_func(case)
# 获取LLM对问题的解答
response = get_response(prompt, \"LLM\")
# 从完整对话中提取答案
extracted_output = Puzzlebootcamp.extract_output(prompt + response)
# 验证答案并评分
score = Puzzlebootcamp.verify_score(extracted_output, case)
```
## 你的任务
请根据以下谜题描述(谜题描述可能不完整,请先结合你的知识澄清规则),实现一个完整的谜题训练场类:
### 谜题描述
Binairo is a logic puzzle played on a rectangular grid (typically square and even-sized, e.g., 6x6, 8x8). The goal is to fill the grid with **0s and 1s** while adhering to these rules:
1. **Balance**:
Each row and column must contain an **equal number of 0s and 1s** (e.g., in an 8x8 grid, every row/column has four 0s and four 1s).
2. **No Triples**:
No three identical digits (0 or 1) can appear consecutively **in a row or column**. For example, \"000\" or \"111\" is invalid.
3. **Uniqueness**:
Each row must be **unique**, and each column must also be **unique**. Duplicate rows or columns are forbidden.
4. **Solution Uniqueness**:
The entire grid must have **exactly one valid solution** determined by logical deduction, with no guesswork required.
The puzzle starts with some cells pre-filled as clues, and players use elimination and pattern-matching to deduce the remaining cells.
请完成上述谜题的训练场环境类实现,包括所有必要的方法。
"""
from bootcamp import Basebootcamp
import random
import re
class Binairobootcamp(Basebootcamp):
def __init__(self, size=6, clue_density=0.5):
if size % 2 != 0:
raise ValueError("Size must be even for Binairo puzzle.")
self.size = size
self.clue_density = clue_density
def generate_solution(self):
n = self.size
possible_rows = self.generate_all_possible_rows(n)
random.shuffle(possible_rows)
for _ in range(1000):
try:
selected = random.sample(possible_rows, n)
except ValueError:
continue
if len({tuple(r) for r in selected}) != n:
continue
if self.check_columns(selected, n):
return selected
# Fallback example for 4x4
return [
[0, 1, 0, 1],
[1, 0, 1, 0],
[0, 1, 1, 0],
[1, 0, 0, 1]
]
def generate_all_possible_rows(self, n):
return self.backtrack_row([], n, n//2, n//2)
def backtrack_row(self, current, n, zeros, ones):
if len(current) == n:
return [current.copy()] if zeros == 0 and ones == 0 else []
solutions = []
for bit in [0, 1]:
if (bit == 0 and zeros == 0) or (bit == 1 and ones == 0):
continue
if len(current) >= 2 and current[-1] == bit and current[-2] == bit:
continue
new_current = current.copy()
new_current.append(bit)
new_zeros = zeros - 1 if bit == 0 else zeros
new_ones = ones - 1 if bit == 1 else ones
solutions += self.backtrack_row(new_current, n, new_zeros, new_ones)
return solutions
def check_columns(self, grid, n):
columns = list(zip(*grid))
for col in columns:
if col.count(0) != n//2 or col.count(1) != n//2:
return False
for i in range(len(col)-2):
if col[i] == col[i+1] == col[i+2]:
return False
return len(set(columns)) == len(columns)
def case_generator(self):
solution = self.generate_solution()
puzzle = [
[
cell if random.random() < self.clue_density else None
for cell in row
]
for row in solution
]
return {'puzzle': puzzle, 'solution': solution}
@staticmethod
def prompt_func(question_case):
puzzle = question_case['puzzle']
size = len(puzzle)
rows = []
for i, row in enumerate(puzzle, 1):
cells = ['_' if c is None else str(c) for c in row]
rows.append(f"Row {i}: {' '.join(cells)}")
return f"""Solve this Binairo puzzle (size {size}x{size}):
Rules:
1. Equal 0s/1s in each row/column
2. No three consecutive identical digits
3. All rows/columns must be unique
4. Exactly one valid solution
Puzzle:
{chr(10).join(rows)}
Place your final answer between [answer] and [/answer] tags as:
[answer]
1 0 1 0
0 1 0 1
...[/answer]"""
@staticmethod
def extract_output(output):
matches = re.findall(r'\[answer\](.*?)\[/answer\]', output, re.DOTALL)
if not matches:
return None
try:
solution = []
for line in matches[-1].strip().split('\n'):
solution.append([int(c) for c in line.split()])
return solution
except:
return None
@classmethod
def _verify_correction(cls, solution, identity):
expected = identity['solution']
return solution == expected