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108 lines
No EOL
3.9 KiB
Python
Executable file
108 lines
No EOL
3.9 KiB
Python
Executable file
from .BaseCipherEnvironment import BaseCipherEnvironment
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class KorAffineCipherEnvironment(BaseCipherEnvironment):
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def __init__(self, *args, **kwargs):
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problem_description = ''
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super().__init__(problem_description=problem_description,*args, **kwargs)
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@property
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def cipher_name(self) -> str:
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return "Kor_rule5_AffineCipher"
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def encode(self, text, **kwargs):
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# 将输入转换为大写字母并移除非字母字符
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text = ''.join([char.upper() for char in text if char.isalpha()])
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print(f"原始文本: {text}")
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print("开始加密过程...")
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print("使用仿射字母表: XMJQUDONPRGTVBWFAKSHZCYEIL")
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print("参数 A=3, B=5")
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alphabet = "XMJQUDONPRGTVBWFAKSHZCYEIL"
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A = 3
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B = 5
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n = len(alphabet)
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letter_to_index = {char: idx for idx, char in enumerate(alphabet)}
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encrypted_message = []
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for char in text:
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if char in letter_to_index:
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x = letter_to_index[char]
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y = (A * x + B) % n
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print(f"字符 {char} -> 位置 {x} -> 计算(3*{x}+5)%26={y} -> 加密为 {alphabet[y]}")
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encrypted_message.append(alphabet[y])
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result = ''.join(encrypted_message)
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print(f"加密完成，结果: {result}")
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return result
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def decode(self, text, **kwargs):
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print(f"加密文本: {text}")
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print("开始解密过程...")
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print("使用仿射字母表: XMJQUDONPRGTVBWFAKSHZCYEIL")
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print("参数 A=3, B=5, A的逆元=9")
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alphabet = "XMJQUDONPRGTVBWFAKSHZCYEIL"
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A = 3
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B = 5
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n = len(alphabet)
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letter_to_index = {char: idx for idx, char in enumerate(alphabet)}
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A_inv = 9
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decrypted_message = []
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for char in text:
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if char in letter_to_index:
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y = letter_to_index[char]
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x = A_inv * (y - B) % n
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print(f"字符 {char} -> 位置 {y} -> 计算9*({y}-5)%26={x} -> 解密为 {alphabet[x]}")
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decrypted_message.append(alphabet[x])
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result = ''.join(decrypted_message)
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print(f"解密完成，结果: {result}")
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return result
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def get_encode_rule(self, ):
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return """加密规则:
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- 输入:
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- 明文: 仅包含大写字母的字符串，不含标点和空格
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- 输出:
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- 密文: 大写字母字符串
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- 准备:
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- 仿射字母表 = "XMJQUDONPRGTVBWFAKSHZCYEIL"
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- 将每个字母与其在仿射字母表中的位置关联（从0开始）:
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X->0, M->1, J->2, Q->3, U->4, D->5, O->6, N->7,
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P->8, R->9, G->10, T->11, V->12, B->13, W->14, F->15,
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A->16, K->17, S->18, H->19, Z->20, C->21, Y->22, E->23, I->24, L->25
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- A: 3
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- B: 5
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- A_inv: 9
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- 加密步骤:
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- 对于每个明文字符p:
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- 设x为其在仿射字母表中的位置
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- 应用仿射编码函数计算y:
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- y = (Ax + B) mod 26
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- 在仿射字母表中找到位置y对应的字母，形成加密消息"""
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def get_decode_rule(self, ):
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return """解密规则:
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- 输入:
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- 密文: 大写字母字符串
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- 输出:
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- 明文: 大写字母字符串
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- 准备:
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- 仿射字母表 = "XMJQUDONPRGTVBWFAKSHZCYEIL"
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- 将每个字母与其在仿射字母表中的位置关联（从0开始）:
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X->0, M->1, J->2, Q->3, U->4, D->5, O->6, N->7,
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P->8, R->9, G->10, T->11, V->12, B->13, W->14, F->15,
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A->16, K->17, S->18, H->19, Z->20, C->21, Y->22, E->23, I->24, L->25
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- A: 3
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- B: 5
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- A_inv: 9
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- 解密步骤:
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- 对于每个密文字符c:
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- 设y为其在仿射字母表中的位置
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- 计算x:
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- x = A_inv * (y - B) % n
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- 用仿射字母表中位置x处的字母替换c，形成解密消息"""
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