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* feat(run_eval): add checkpoint resume functionality and update example documentation; - update new bootcamp benchmark dataset * refactor(data_pipeline): optimize data generation pipeline; add multiple preset configurations for data generation * docs: update bootcamp list and add new scripts - Update Fulllist_InternBootcamp.md with new bootcamps and categories - Add new scripts to .gitignore: - examples/pipelines/filter_autogen_configs.py - examples/pipelines/quickgen_data_configs_from_eval_meta.py - Update dependencies in setup.py: - Add scipy and scikit-learn * refactor(internbootcamp): update bootcamp modules and improve error handling - Update import statements in __init__.py files - Add timestamp to target directory name in verl_data_preprocess.py - Improve error handling and scoring logic in bootcamp_judger.py - Remove unnecessary comments and update puzzle descriptions in multiple files
152 lines
5 KiB
Python
Executable file
152 lines
5 KiB
Python
Executable file
"""### 谜题描述
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Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into three pieces so that the sum of numbers from each piece is equal to the sum of numbers from any other piece, and each piece contains positive integer amount of squares. Would you help Bob solve this problem?
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Input
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The first input line contains integer n (1 ≤ n ≤ 105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value.
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Output
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Output the amount of ways to cut the stripe into three non-empty pieces so that the sum of numbers from each piece is equal to the sum of numbers from any other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only.
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Examples
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Input
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4
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1 2 3 3
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Output
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1
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Input
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5
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1 2 3 4 5
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Output
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0
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Here is a reference code to solve this task. You can use this to help you genereate cases or validate the solution.
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```python
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n=input()
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c={}
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a=map(int,raw_input().split())
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w,s,t=0,sum(a),0
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for x in a[:-1]:
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v=s-t-x
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if v+v==t+x:w+=c.get(v,0)
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t+=x
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c[t]=c.get(t,0)+1
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print (0,w)[n>2]
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```
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请完成上述谜题的训练场环境类实现,包括所有必要的方法。
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"""
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from bootcamp import Basebootcamp
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import random
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import re
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from bootcamp import Basebootcamp
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class Cstripe2bootcamp(Basebootcamp):
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def __init__(self, n_min=3, n_max=100, allow_unsolvable=True, force_solvable=False):
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self.n_min = max(3, n_min)
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self.n_max = n_max
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self.allow_unsolvable = allow_unsolvable
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self.force_solvable = force_solvable
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def case_generator(self):
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generate_solvable = self.force_solvable or not self.allow_unsolvable
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if generate_solvable:
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n = random.randint(self.n_min, self.n_max)
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if n < 3:
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n = 3
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total_sum = random.randint(-3000, 3000) * 3 # 确保总和是3的倍数
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target = total_sum // 3
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def generate_segment(length, segment_target):
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if length == 0:
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return []
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while True:
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# 最后一个元素在有效范围内
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last = random.randint(-10000, 10000)
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needed_sum = segment_target - last
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# 生成前length-1个元素
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if length-1 == 0:
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if needed_sum == 0:
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return [last]
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else:
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continue
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elements = [random.randint(-10000, 10000) for _ in range(length-1)]
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adj = needed_sum - sum(elements)
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if -10000 <= adj <= 10000:
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elements.append(adj)
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# 再次校验所有元素范围
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if all(-10000 <= x <= 10000 for x in elements):
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return elements + [last]
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# 生成三段(确保每段长度至少1)
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len1 = random.randint(1, n-2)
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len2 = random.randint(1, n - len1 -1)
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len3 = n - len1 - len2
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part1 = generate_segment(len1, target)
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part2 = generate_segment(len2, target)
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part3 = generate_segment(len3, target)
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array = part1 + part2 + part3
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return {'n': n, 'array': array}
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else:
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n = random.randint(self.n_min, self.n_max)
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array = [random.randint(-10000, 10000) for _ in range(n)]
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return {'n': n, 'array': array}
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@staticmethod
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def prompt_func(question_case):
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n = question_case['n']
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array = question_case['array']
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array_str = ' '.join(map(str, array))
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return f"""Bob's paper stripe has {n} squares with numbers: {array_str}. Find how many ways to cut it into three non-empty parts with equal sums. Put your answer in [answer]...[/answer]. Example: [answer]1[/answer]."""
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@staticmethod
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def extract_output(output):
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answers = re.findall(r'\[answer\]\s*(\d+)\s*\[/answer\]', output)
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return int(answers[-1]) if answers else None
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@classmethod
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def compute_solution(cls, n, array):
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if n < 3:
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return 0
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total = sum(array)
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if total % 3 != 0:
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return 0
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target = total // 3
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first_cut = 0
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count = 0
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current = 0
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for i in range(n-1):
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current += array[i]
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if current == 2 * target:
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count += first_cut
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if current == target:
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first_cut += 1
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return count
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@classmethod
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def _verify_correction(cls, solution, identity):
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try:
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user_ans = int(solution)
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except:
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return False
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n = identity['n']
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array = identity['array']
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return user_ans == cls.compute_solution(n, array)
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