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* feat(run_eval): add checkpoint resume functionality and update example documentation; - update new bootcamp benchmark dataset * refactor(data_pipeline): optimize data generation pipeline; add multiple preset configurations for data generation * docs: update bootcamp list and add new scripts - Update Fulllist_InternBootcamp.md with new bootcamps and categories - Add new scripts to .gitignore: - examples/pipelines/filter_autogen_configs.py - examples/pipelines/quickgen_data_configs_from_eval_meta.py - Update dependencies in setup.py: - Add scipy and scikit-learn * refactor(internbootcamp): update bootcamp modules and improve error handling - Update import statements in __init__.py files - Add timestamp to target directory name in verl_data_preprocess.py - Improve error handling and scoring logic in bootcamp_judger.py - Remove unnecessary comments and update puzzle descriptions in multiple files
122 lines
4.8 KiB
Python
Executable file
122 lines
4.8 KiB
Python
Executable file
"""### 谜题描述
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**Objective**: Clear a rectangular grid of hidden cells without detonating any mines. Cells contain either mines or numbers indicating adjacent mines.
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**Grid Setup**:
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1. The grid consists of hidden cells, some containing mines (randomly placed).
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2. Non-mine cells reveal a number when uncovered, representing the total mines in the 8 adjacent cells (vertically, horizontally, and diagonally).
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**Gameplay**:
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1. **Uncover a Cell**: Click/select a cell to reveal its content:
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- If it contains a mine, the game ends (loss).
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- If it shows a number, use this to deduce nearby mine locations.
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- If it shows **0** (no adjacent mines), all adjacent cells automatically uncover recursively until numbered cells are reached.
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2. **Flagging Mines**: Right-click/mark a cell to flag it as a suspected mine (prevents accidental uncovering). Flags help track potential mines but do not affect gameplay logic otherwise.
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**Win Condition**:
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- All non-mine cells are uncovered, and all mines are correctly flagged.
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**Logic Rules**:
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- Numbers on the grid are **static hints**, not live updates. Flagging a mine does not change existing numbers.
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- Use the numbers to infer mine positions: e.g., a cell labeled \"3\" must have exactly 3 mines in its 8 neighboring cells.
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**Loss Condition**:
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- Uncovering any cell containing a mine.
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请完成上述谜题的训练场环境类实现,包括所有必要的方法。
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"""
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from bootcamp import Basebootcamp
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import random
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import re
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import ast
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class Minesweeperbootcamp(Basebootcamp):
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def __init__(self, rows=8, cols=8, mines_count=10):
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if mines_count > rows * cols:
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raise ValueError("Number of mines cannot exceed grid size.")
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self.rows = rows
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self.cols = cols
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self.mines_count = mines_count
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def case_generator(self):
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all_cells = [(i, j) for i in range(self.rows) for j in range(self.cols)]
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if self.mines_count > len(all_cells):
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raise ValueError("mines_count exceeds valid cells count.")
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mines = random.sample(all_cells, self.mines_count)
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mines_list = [list(coord) for coord in mines]
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return {
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'rows': self.rows,
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'cols': self.cols,
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'mines': mines_list
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}
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@staticmethod
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def prompt_func(question_case):
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rows = question_case['rows']
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cols = question_case['cols']
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mines_count = len(question_case['mines'])
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mines_set = set(tuple(coord) for coord in question_case['mines'])
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grid_info = []
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for i in range(rows):
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for j in range(cols):
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count = 0
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for dx in (-1, 0, 1):
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for dy in (-1, 0, 1):
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if dx == 0 and dy == 0:
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continue
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x, y = i + dx, j + dy
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if 0 <= x < rows and 0 <= y < cols and (x, y) in mines_set:
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count += 1
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grid_info.append((i, j, count))
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prompt = (
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f"You are playing Minesweeper on a {rows}x{cols} grid with {mines_count} mines.\n"
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"Each number below represents the count of adjacent mines for a cell. "
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"Find all the mine locations and provide them in the specified format.\n\n"
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"Revealed cells (format: row, column: count):\n"
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)
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for i, j, num in grid_info:
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prompt += f"- ({i}, {j}): {num}\n"
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prompt += (
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"\nYour answer must be a list of mine coordinates formatted as [[row1, col1], [row2, col2], ...]. "
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"Place your final answer between [answer] and [/answer]."
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)
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return prompt
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@staticmethod
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def extract_output(output):
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pattern = r'\[answer\](.*?)\[/answer\]'
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matches = re.findall(pattern, output, re.DOTALL)
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if not matches:
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return None
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last_match = matches[-1].strip()
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try:
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solution = ast.literal_eval(last_match)
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if (isinstance(solution, list) and
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all(isinstance(coord, list) and len(coord) == 2 for coord in solution)):
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return solution
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return None
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except (SyntaxError, ValueError):
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return None
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@classmethod
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def _verify_correction(cls, solution, identity):
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if not isinstance(solution, list):
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return False
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try:
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solution_set = {tuple(coord) for coord in solution}
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except TypeError:
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return False
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mines = identity.get('mines', [])
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mines_set = {tuple(mine) for mine in mines}
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if len(solution_set) != len(mines_set):
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return False
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rows, cols = identity['rows'], identity['cols']
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for (r, c) in solution_set:
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if not (0 <= r < rows and 0 <= c < cols):
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return False
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return solution_set == mines_set
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