mirror of
https://github.com/open-thought/reasoning-gym.git
synced 2026-04-28 17:29:39 +00:00
Still experimenting
This commit is contained in:
parent
b0e70008ea
commit
b203353751
357 changed files with 2888 additions and 0 deletions
8
reasoning_gym/data/gsm_data/p1/0095.json
Normal file
8
reasoning_gym/data/gsm_data/p1/0095.json
Normal file
|
|
@ -0,0 +1,8 @@
|
|||
{
|
||||
"question": "There are 6 students playing tennis and twice that number playing volleyball. There are 16 boys and 22 girls playing soccer. If each student only participates in one group, how many students are there in total?",
|
||||
"answer": "There are 6 x 2 = <<6*2=12>>12 students playing volleyball.\nThere are 16 + 22 = <<16+22=38>>38 students playing soccer.\nIn total there are 6 + 12 + 38 = <<6+12+38=56>>56 students.\n#### 56",
|
||||
"id_orig": 918,
|
||||
"id_shuffled": 95,
|
||||
"question_annotated": "There are {n1,6} students playing {sport1,tennis} and {mult,twice} that number playing {sport2,volleyball}. There are {n2,16} boys and {n3,22} girls playing {sport3,soccer}. The number of students playing {sport4,badminton} is {mult2,three times} the combined number of students who play other sports. If each student only participates in one sport, how many students are there in total?\n\n#init:\n- sport1, sport2, sport3, sport4 = sample(['basketball', 'badminton', 'table tennis', 'football', 'volleyball', \"golf\"], 4)\n- $mult = sample(multiple_ice+multi_times)\n- $mult2 = sample(multiple_ice+multi_times)\n- $n1 = range(4, 21)\n- $n2 = range(10, 31)\n- $n3 = range(10, 31)\n\n#conditions:\n- n1 * mult + n2 + n3 <= 250\n\n#answer: (n1 + n1 * mult[1] + n2 + n3) * (mult2 + 1)",
|
||||
"answer_annotated": "There are {n1} x {mult} = <<{n1}*{mult}={n1*mult}>>{n1*mult} students playing {sport2}.\nThere are {n2} + {n3} = <<{n2}+{n3}={n2+n3}>>{n2+n3} students playing {sport3}.\nThere are {n1} + {n1*mult} + {n2+n3} = <<{n1}+{n1*mult}+{n2+n3}={n1 + n1*mult + n2 + n3}>>{n1 + n1*mult + n2 + n3} students playing {sport1}, {sport2}, or {sport3}.\nThe number of students playing {sport4} is {mult2} times that amount which will be {mult2} * {n1 + n1*mult + n2 + n3} = {mult2*(n1 + n1*mult + n2 + n3)}. \nIn total, there are {n1 + n1*mult + n2 + n3}+{mult2*(n1 + n1*mult + n2 + n3)} = {(n1 + n1*mult + n2 + n3)*(mult2+1)} students in total.\n#### {(n1 + n1*mult + n2 + n3)*(mult2+1)}"
|
||||
}
|
||||
Loading…
Add table
Add a link
Reference in a new issue