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abdulhakeem 2025-01-30 23:44:12 -06:00
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{
"question": "Peter wants to make different sized ice cubes with 32 ounces of water. He can make giant cubes that use 4 ounces per cube, medium cubes that use 2 ounces, and small cubes that use 1/2 an ounce. If he makes 3 giant cubes, 7 medium cubes, and 8 small cubes, how many ounces of water does he have left?",
"answer": "The giant cubes used up 12 ounces of water because 3 times 4 equals <<3*4=12>>12.\nThe medium cubes used up 14 ounces of water because 7 times 2 equals <<7*2=14>>14.\nThe small cubes used up 4 ounces of water because 8 times 1/2 equals 4.\nThis means that Peter has used up 30 ounces of water because 12 plus 14 plus 4 equals 30.\nPeter has 2 ounces of water left because 32 minus 30 equals <<32-30=2>>2.\n#### 2",
"id_orig": 737,
"id_shuffled": 11,
"question_annotated": "{name, Peter} wants to make different sized ice cubes with {n,32} {unit,ounce}s of water. He can make giant cubes that use {w1,4} {unit,ounce}s per cube, medium cubes that use {w2,2} {unit,ounce}s, small cubes that use {w3,1/2} of {unit,ounce}, and tiny cubes that are half the size of small cubes. If he makes {n1,3} giant cubes, {n3,8} small cubes, {n2,7} medium cubes, and eight tiny cubes, how many {unit,ounce}s of water does he have left?\n\n#init:\n- name = sample(names_male)\n- unit = sample(weights_sm)\n- $w1 = range(7, 14)\n- $w2 = range(11, 16)\n- $w3 = fraction_nums\n- $n1 = range(8, 12)\n- $n2 = range(12, 16)\n- $n3 = sample([14, 24, 15])\n- $n = range(250, 350, 2)\n- $ans = range(60, 101, 2)\n\n#conditions:\n- w3 < w2 < w1\n- is_int(n3 * w3)\n- is_int(4*w3)\n- ans == n - (n1*w1) - (n2*w2) - int(n3*w3) - int(8*w3/2)\n\n#answer: ans",
"answer_annotated": "The giant cubes used up {n1} {unit}s of water because {n1} times {w1} equals <<{n1}*{w1}={n1*w1}>>{n1*w1}.\nThe medium cubes used up {n2*w2} {unit}s of water because {n2} times {w2} equals <<{n2}*{w2}={n2*w2}>>{n2*w2}.\nThe small cubes used up {int(w3*n3)} {unit}s of water because {n3} times {w3} equals {int(n3*w3)}.\nThe tiny cubes are 8 * 0.5 * {w3} = {int(4 * w3)}.\nThis means that {name} has used up {int(n3*w3+n2*w2+n1*w1)+int(4 * w3)} {unit}s of water because {n1*w1} plus {n2*w2} plus {int(w3*n3)} plus {int(4 * w3)} equals {int(n3*w3+n2*w2+n1*w1)+int(4 * w3)}.\n{name} has {ans} {unit}s of water left because {n} minus {int(n3*w3+n2*w2+n1*w1)+int(4 * w3)} equals <<{n}-{int(n3*w3+n2*w2+n1*w1)+int(4 * w3)}={ans}>>{ans}.\n#### {ans}"
}