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8 lines
No EOL
2.1 KiB
JSON
8 lines
No EOL
2.1 KiB
JSON
{
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"question": "John and Jack have 30 minutes to walk to school together. It takes them 6 minutes to get to the corner where the library is. It takes them another 13 minutes to get to the fire station. How much longer do they have to get to school without being late?",
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"answer": "John and Jack arrive at the library with 30 - 6 = <<30-6=24>>24 minutes left to reach the fire station.\nThey then arrive at the fire station and have 24 - 13 = <<24-13=11>>11 minutes left to get to school without being late.\n#### 11",
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"id_orig": 684,
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"id_shuffled": 14,
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"question_annotated": "{n1,John} and {n2,Jack} have {t,30} minutes to walk to {loc1,school} together. It takes them {t1,6} minutes to get to the corner where the {loc2,library} is. It takes them another {t2,13} minutes to get to the {loc3, fire station}. It will then take {mult,double} the combined amount they have spent so far to reach the {loc4, grocery store}. How much longer do they have to get to {loc1,school} without being late, if they have already wasted {waste,10} minutes to get a coffee before their walk?\n\n#init:\n- n1, n2 = sample(names, 2)\n- loc1, loc2, loc3, loc4 = sample(['cinema', 'mall', 'library', 'park', 'gym', 'bank', 'grocery store'], 4)\n- $t1 = range(10, 30)\n- $t2 = range(10, 70)\n- $t = range(130, 270)\n- $waste = range(22, 54)\n- $mult = sample(multiple)\n\n#conditions:\n- not divides(t1, 5)\n- not divides(t2, 5)\n- not divides(t, 5)\n- t > (t1 + t2)*(1+mult) + waste\n\n#answer: t - waste - ((t1 + t2)*(1+mult))",
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"answer_annotated": "{n1} and {n2} arrive at the {loc2} with {t} - {t1} = <<{t}-{t1}={t-t1}>>{t-t1} minutes left to reach the {loc3}.\nThey then arrive at the {loc2} and have {t-t1} - {t2} = <<{t-t1}-{t2}={t-t1-t2}>>{t-t1-t2} minutes left to get to {loc1} without being late.\nThen they have to spent {t1+t2} * {mult} = {mult*t1+mult*t2}. So In total they will have {t-t1-t2}-{mult*t1+mult*t2} = {t-(t1+t2)*(1+mult)}.\nSince they wasted {waste} minutes, we deduce that they have {t-(t1+t2)*(1+mult)} - {waste} = {(t-(t1+t2)*(1+mult))-waste} minutes.\n#### {t-waste-((t1+t2)*(1+mult))}"
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} |