reasoning-gym/reasoning_gym/data/gsm_data/p1/0066.json
2025-01-30 23:51:31 -06:00

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{
"question": "Candy has 15 light blue spools of thread, 45 dark blue spools of thread, 40 light green spools of thread, and 50 dark green spools of thread. What percent of her spools are blue?",
"answer": "First find the number of blue spools: 15 spools + 45 spools = <<15+45=60>>60 spools\nThen find the total number of spools: 40 spools + 50 spools + 60 spools = <<40+50+60=150>>150 spools\nThen divide the number of blue spools by the total number of spools and multiply by 100% to express the answer as a percentage: 60 spools / 150 spools * 100% = 40%\n#### 40",
"id_orig": 728,
"id_shuffled": 66,
"question_annotated": "{name,Candy} has {n1,15} light {c1,blue} spools of thread, {n2,45} dark {c1,blue} spools of thread, {n3,40} light {c2,green} spools of thread, and {n4,50} dark {c2,green} spools of thread. She also has {mult,twice} as many {c3,red} spools as {c1,blue} spools. What percent of her spools are {c1,blue}?\n\n#init:\n- name = sample(names_female)\n- c1, c2, c3 = sample(colors, 3)\n- $n1 = range(15, 50)\n- $n2 = range(11, 50)\n- $n3 = range(20, 60)\n- $n4 = range(10, 25)\n- $mult = sample(multi_times)\n\n#conditions:\n- is_int(100 * (n1 + n2) / (n1 + n2 + n3 + n4 + mult*(n1+n2)))\n\n#answer: int(100 * (n1 + n2) / (n1 + n2 + n3 + n4+mult*(n1+n2)))",
"answer_annotated": "First find the number of {c1} spools: {n1} spools + {n2} spools = <<{n1}+{n2}={n1+n2}>>{n1+n2} spools.\nThen we find the number of {c3} spools: {mult}*{n1+n2} = {mult*(n1+n2)}.\nThen find the total number of spools: {n3} spools + {n4} spools + {n1+n2} spools + {mult*(n1+n2)} spools = <<{n3}+{n4}+{n1+n2}+{mult*(n1+n2)}={n1+n2+n3+n4+mult*(n1+n2)}>>{n1+n2+n3+n4+mult*(n1+n2)} spools\nThen divide the number of {c1} spools by the total number of spools and multiply by 100% to express the answer as a percentage: {n1+n2} spools / {n1+n2+n3+n4+mult*(n1+n2)} spools * 100% = {int(100 * (n1 + n2) / (n1 + n2 + n3 + n4+mult*(n1+n2)))}%\n#### {int(100 * (n1 + n2) / (n1 + n2 + n3 + n4+mult*(n1+n2)))}"
}